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3 years ago

there are 720 children in our school. 5/8 of them have dark hair. How many children have blonde or red hair?

1 answer:

7 0

Assuming that the red and blonde hair are considered the 3/8ths of the school with light hair, 270 children in the school have red or blonde hair.

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Order the following numbers from least to greatest -9/2 0 1 3/5 9/7 2/3

marysya [2.9K]

$\frac{-9}{2}$

$\frac{2}{3}$

$\frac{9}{7}$

1 $\frac{3}{5}$

3 0

3 years ago

Read 2 more answers

the ratio of apples to oranges in a fruit basket is 12:4 if there are 7 oranges in the fruit basket then how many apples and ora

Ugo [173]

Just simple proportions:

12(apples) x(apples)
-------------- = --------------
4(oranges) 7(oranges)

12*7 = 84
84/4 = 21

There are 21 apples + 7 oranges = 28 apples and oranges!

7 0

3 years ago

Namd the terms in the expression 3n + 4p + 2

Jobisdone [24]

The terms are 3n, 4p, and 2.

4 0

3 years ago

The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

3 years ago

Please help me with 13 and 15 asap

Law Incorporation [45]

Gosh, I've done this problem before. Let's start with 13. In this problem, we're basically just skip counting. For example, in the roses row, in the second bouquet, we know we have to add 4 more flowers, so we can document 8. Continue to skip count for both. For 15, we would have about 96 more movie posters remaining, making our ratio 96:x. So, 96:x = 120:100. Therefore, x would equal 80- as 96:80 equals 120:100. If she needs 80 and already had 100, she should sell 20 posters. Hope this helped.

3 0

3 years ago