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I am Lyosha [343]
3 years ago
15

How do i factor the expressions 4w-16?

Mathematics
1 answer:
igomit [66]3 years ago
7 0
The answer to this would be 4(w-4)
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The table below shows the weekly change in the price of one gram of gold for four weeks.
Sonja [21]

Answer:

THEY DIDN'T IT WAS BECAUSE THEY MADE UP A FAKE RUMER AND HAD TO MAKE IT LOOK REAL

Step-by-step explanation:

8 0
3 years ago
I dont get this question.
SashulF [63]
It is 12 - 2/3 = 18, then solve :)
hope that helps :D
8 0
3 years ago
RIGHT ANSWER WILL BE MARK BRAINLIEST
nirvana33 [79]
...............the answer is D
6 0
3 years ago
Read 2 more answers
Can someone help me please?
Elena-2011 [213]
<h3>Answer:  4368 square feet</h3>

======================================================

Explanation:

Check out the diagram below

I drew a rectangle with dimensions 56 ft by 78 ft.

Then I broke up the 56 into 50+6, and I broke up the 78 into 70+8

The reason for this is because it's fairly easy to multiply the areas of each smaller rectangle at this point

  • In the upper left corner, we have an area of 50*70 = 3500. Note how this is basically 5*7 = 35, but we tack on the two zeros (from 50 and 70 combined)
  • In the upper right corner, we have an area of 70*6 = 420
  • In the lower left corner, we have an area of 50*8 = 400
  • In the lower right corner, we have an area of 6*8 = 48

Add up all the areas found: 3500+420+400+48 = 4368

As a way to check, using your calculator shows that 56*78 = 4368

8 0
2 years ago
In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,
aivan3 [116]

Answer:

Case 1:

AB = 30

BC = 50

Case 2:

AB = 15.9

BC = 36.7

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

AB^2 = AN^2 + BN^2

This gives:

AB^2 = 24^2 + 18^2

AB^2 = 576 + 324

AB^2 = 900

Take square roots of both sides

AB = \sqrt{900

AB = 30

To calculate BC, we consider ANC, where:

AC^2 = AN^2 + NC^2

40^2 = 24^2 + NC^2

1600 = 576 + NC^2

Collect like terms

NC^2 = 1600 - 576

NC^2 = 1024

Take square roots

NC = \sqrt{1024

NC = 32

So:

BC = NC + BN

BC = 32 + 18

BC = 50

Case 2:

Using Pythagoras theorem in ANB, we have:

AN^2 = AB^2 + BN^2

This gives:

24^2 = AB^2 + 18^2

576 = AB^2 + 324

Collect like terms

AB^2 = 576 - 324

AB^2 = 252

Take square roots of both sides

AB = \sqrt{252

AB = 15.9

To calculate BC, we consider ABC, where:

AC^2 = AB^2 + BC^2

40^2 = 252 + BC^2

1600 = 252 + BC^2

Collect like terms

BC^2 = 1600 - 252

BC^2 = 1348

Take square roots

BC = \sqrt{1348

BC = 36.7

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0
2 years ago
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