Given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:
- Segment bisector of XY = line n
- Length of XY = 6
<em><u>Recall:</u></em>
- A line that divides a segment into two equal parts is referred to as segment bisector.
In the diagram attached below, line n divides XY into XM and MY.
Thus, the segment bisector of XY is: line n.
<em><u>Find the value of x:</u></em>
XM = MY (congruent segments)
- Collect like terms and solve for x
XY = XM + MY
Therefore, given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:
- Segment bisector of XY = line n
- Length of XY = 6
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We need to get the limits first. When y = 0
0 = 64x - 8x^2
x = 0 and x = 8
The volume is
V = ∫ y dx from 0 to 8
V = ∫ (64x - 8x^2) dx from 0 to 8
V = 32x^2 - 8x^3/3 from 0 to 8
V = 682.67<span />
Answer:
√50= 5√2
Step-by-step explanation:
50=25*2
√50=√25*2
√50=√5*5*2
√50= 5√2
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours
547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000
x = no. of times owner-occupied units had a water supply stoppage.
<h3>What is the probability at x =0?</h3>
P(x=0) = 547000/14770000
P(x=0) = 0.0370
Similarly, we have at x=1
P(x=1) = 5012000/14770000
P(x=1) = 0.3393
P(x=2) = 6110000/14770000
P(x=2) = 0.4137
P(x=3) = 2544000/14770000
P(x=3) = 0.1722
P(x=4) = 557000/14770000
P(x=4) = 0.0378
x f(x)
0 0.0370
1 0.3393
2 0.4137
3 0.1722
4 0.0378
Total 1
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
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Answer:
t=-6
Step-by-step explanation:
