Answer:
<h3>
Step-by-step explanation:</h3>
The z-value is computed from ...
... z = (x -µ)/σ
... z = (184 -206)/10 = -2.2 . . . . for $184
... z = (200 -206)/10 = -0.6 . . . . for $200
You can look up these values in a normal distribution table, or you can use an appropriate calculator to find the corresponding percentiles.
... -2.2 corresponds to the 1.390 percentile. (That amount of area is below -2.2 standard deviations from the mean.)
... -0.6 corresponds to the 27.425 percentile.
Subtracting the two percentages gives the percentage of expenses between $184 and $200. That number is 26.035% ≈ 26%.
_____
<em>Comment on the calculator display</em>
The difference that got cut off from the display in the attachment is ...
... 0.2603496703
The <em>normalcdf( )</em> function requires a lower limit. Using -8 standard deviations is effectively equivalent to -∞ for this purpose, as any lower number has no effect on the least-significant digits of the result.
Answer:
x = 14
Step-by-step explanation:
First put it into slope intercept form
20 = 2x - 8
Move the variable to the left hand side and change its symbol
-2x + 20 = -8
Move the constant to the right hand side and change its symbol
-2x = -8 - 20
Calculate the difference
-2x = -28
Divide both sides of the equation by -2
x = 14
Solution
X = 14
divide 50 by 6.2, because 6.2 and x are entangled by multiplication. once you do that, you will have your answer. it should be 8.06
Well the answer is No.A remainder will always be smaller than the divisor ,because the divisor is the one that used to divide the dividend and the remaining number that cannot be divided by the divisor is called the remainder.
Questions?
Answer:
65.45
Step-by-step explanation:
Zscore = (x - mean) / standard deviation
x = score
Percentage below C :
D = 18% ; F = 12%
Sum = 30%
Obtain the Zscore for the proportion below D
P(Z < 0.30) = -0.524
Hence, Zscore = -0.524
Put Zscore = -0.524 in the equation :
-0.524 = (x - 72) / 12.5
-0.524 * 12.5 = x - 72
-6.55 = x - 72
-6.55 + 72 = x
x = 65.45
To receive a grade of C or better, score must be atleast 65.45
