Here you go :) . . . . ..
Answer:
<u><em>For x - y = 2</em></u>
You need to find x or y in one of the equations and then substitute that into the other.
So we have;
x-y=2
4x-3y=11
We will take the first equation and find x;
x-y=2
add y to both sides;
x-y+y=2+y
x=2+y
Now we take that answer and substitute it forx in the other equation;
4(2+y)-3y=11
8+4y-3y=11
8+y=11
y=3
Now we have what y equals, so we use it in the first equation to find x;
x-3=2
x=5
So we have;
x=5; y=3
Hope you understand!
=)
<u><em>And for 4x – 3y = 11</em></u>
Multiply the first equation by 2 and the second by 3 so that there are the same number of y's in each:
8x - 6y = 22 ...(3)
30x + 6y = -3 ...(4)
Now add (3) and (4) term by term:
38x + 0 = 19
or
38x = 19
or x = 1/2
Put this back into equation (1)
4*(1/2) - 3y = 11
or
2 - 3y = 11
Subtract 2 from both sides:
-3y = 9
Divide both sides by -3
y = -3
Answer:
= 3n + 4
Step-by-step explanation:
there is a common difference between consecutive terms , that is
10 - 7 = 13 - 10 = 16 - 13 = 3
this indicates the sequence is arithmetic with nth term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
here a₁ = 7 and d = 3 , then
= 7 + 3(n - 1) = 7 + 3n - 3 = 3n + 4
Answer:
C. It is not a good fit because there are no points on the line.
Step-by-step explanation:
In order for a line to be a good fit for a data set represented as a scatterplot, the line must follow the general trend of the data in the scatterplot. This line does not follow the general trend of the data on the scatterplot, thus option (C) is the best statement to describe the situation.
C. It is not a good fit because there are no points on the line.
