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kumpel [21]
2 years ago
13

The sum of two numbers is 24 and there quotent is 3

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
7 0

Answer:

36 and -12

Step-by-step explanation:

One of the numbers is x then the second number will be 24-x

\frac{x}{24-x}  = 3

x = 72 - 3x

x = 36

therefore the second number -12

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What is the range of the function graphed below?
aleksandrvk [35]

Answer:       B.     [–4, 0)  ∪  [2, ∞)

To find the range, find out what y-values are possible for the function in the graph.

<h2>Symbols</h2>

We need to pay attention to what symbols to use.

<h3>Reading the diagram</h3>

Solid circle

  • The function touches the point.

Empty circle

  • The function gets close, but does not touch the point.

Arrow

  • The function keeps going to infinity.

<h3>Writing range in set notation</h3>

Square brackets: [ and ]

  • These show that the function touches the point.

Curved brackets: ( and )

  • These show that the function gets close but does not touch the point.
  • Infinity always uses a curved bracket.

Union of sets: ∪

  • This symbol shows that sets of values are talking about the same thing. It's almost like the word 'and'.

<h2>Finding the range of the graphed function</h2><h3>Lower blue line</h3>

Let's start by looking for the lowest possible y-value at the bottom of the diagram. On the graph, the point (4, –4) marked with a solid circle.

The function touches the point and stops. Since the y-value is –4, the lowest possible y-value is:     -4

If we follow the blue line upwards, we find an empty circle at (0, 0). The y-value in (0, 0) is 0. This means that the function gets close, but does not include:     0

So, the first part of our range is:

  • [–4, 0)

<h3>Upper blue line</h3>

The blue line on the top starts where y = 2 at a solid circle. So, the function includes the y-value:    2

If we follow this blue line upwards, it ends with an arrow. This means it will keep going to infinity, which is the symbol:    \infty

So, the second part of our range is:

  • [2, ∞)

<h2>Putting it together</h2>

Put the lower and upper blue lines together with the union of sets symbol. The range is expressed as:    [–4, 0)  ∪  [2, ∞)

Learn more about domain and range here:

brainly.com/question/20349151

4 0
1 year ago
2x - 3 &lt; 9 what is the answer
pogonyaev
2x - 3 < 9
+ 3
2x < 12
÷ 2
x < 6
Hope this helps!
3 0
3 years ago
Read 2 more answers
If θ is a first-quadrant angle in standard position with P(u, v) = (3, 4), evaluate cos 2 θ . -7/25 -1/5 7/25
Grace [21]

Answer:

-7/25.

Step-by-step explanation:

From the given point P we see that the hypotenuse =  √(3*2 + 4^2) = 5.

So cos  θ = 3/5

cos 2 θ =  2 cos^2 θ - 1

= 2 * (3/5)^2 -1

= -7/25.

6 0
3 years ago
The density d kg/m3 of a cube of mass m kilograms and side length x meters is given by the formula:  What is the value of d if
bearhunter [10]

Answer:

5000kg/m3

Step-by-step explanation:

Its easy to get the answer of a question from the unit.

So, it will be mass over metre cube.

Therefore, m=40kg x= (0. 2)^3 =0. 008m

40/0. 008 = 5000kg/m^3

6 0
2 years ago
A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to
melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}

Mean of X:

E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42

Variance of X:

E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}

var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58

5 0
3 years ago
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