The sum of slopes of lines b and c are 0
Yes because 100 percent is 10 hrs so 1 more hr is 110 percent. And if u try to put it in a equation it will be 110%
Answer:
Thus # 2 is correct (5 (y + 4))/2
Step-by-step explanation:
Simplify the following:
(5 y (y^2 - 16))/(2 y (y - 4))
(5 y (y^2 - 16))/(2 y (y - 4)) = y/y×(5 (y^2 - 16))/(2 (y - 4)) = (5 (y^2 - 16))/(2 (y - 4)):
(5 (y^2 - 16))/(2 (y - 4))
y^2 - 16 = y^2 - 4^2:
(5 (y^2 - 4^2))/(2 (y - 4))
Factor the difference of two squares. y^2 - 4^2 = (y - 4) (y + 4):
(5 (y - 4) (y + 4))/(2 (y - 4))
Cancel terms. (5 (y - 4) (y + 4))/(2 (y - 4)) = (5 (y + 4))/2:
Answer: (5 (y + 4))/2
This solution has no solutions because when you do a substitution method you might end up getting rid of the variable and left with a constant.
So its 2$ per guest since
20$/10 guests
2$/1 guest
and if she has 48$ its
48$/24 guests
So she can have 24 guests max if she spends 48$
