19.95x + 9.95y <== ur answer
Answer:
V(hemisphere) = 1072.3in^3
Step-by-step explanation:
To find the volume of a hemisphere, we will have to take the volume of a sphere as a whole and divide it by 2. This is because a hemisphere is half of a sphere.
The volume of a sphere is:
Let's plug in the radium of 8 into the equation and solve:
Now, divide it by 2
V(sphere) = (2144.660585)/2
V(hemisphere) = 1072.3in^3
I hope this helps!!
Message me so I can help, I need a better pocture
There are 60 minutes in one hour. So 5/12 of 60 minutes (1 hr) is 25 minutes.
There are 36 inches in one yard. So 2/3 of 36 inches (1 yard) is 24 inches.
Hope this helps.
Answer:
and 
and b=
Step-by-step explanation:
We are given that a quadratic equation

We have to solve the equation by completing square and find the value of b.






and 

And 
Therefore,
and 
and b=