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zalisa [80]
4 years ago
8

I will rate you a brainlest☆​

Mathematics
2 answers:
algol [13]4 years ago
6 0

Answer:

A.  x  x   1.2  1.5  1.8

B.  3/8   x   x  x  1 2/8

C.  x  x  -3  -2  -1

D.   0  x  x  x  5 1/3

E.   x  x   0.83  0.94  1.05

Step-by-step explanation:

hope it helped

Inessa [10]4 years ago
5 0

Answer:

A 0.6 0.9 1.2 1.5 1.8

B 3/8 5/8 7/8 9/8 11/8

C -7 -5 -3 -2 -1

D 1, 1 1/3, 1 2/3, 2, 2 1/3

E 0.61 0.72 0.83 0.94 1.05

Step-by-step explanation:

You might be interested in
Which equation can be used to prove 1 + tan2(x) = sec2(x)?
notsponge [240]

Answer:

fourth option

Step-by-step explanation:

Using the trigonometric identity

cos²x + sin²x = 1

Divide all terms by cos²x

\frac{cos^2x}{cos^2x} + \frac{sin^2x}{cos^2x} = \frac{1}{cos^2x} which gives

1 + tan²x = sec²x

6 0
3 years ago
Can anyone help me with this? i don’t understand it, thank you.
Alina [70]

Answer:

24

Step-by-step explanation:

It is done by Middle term splitting.

Taking the general equation ax² + bx + c, by middle term splitting, "b" should be splitted such that the numbers either on adding or on subtracting must be equal to "b" and their products must be equal to "a x c".

For example, in the question it's already given that the equation 8x² + bx + c is middle term splitted into 8x² + px + qx + 3.

So, that means "p x q" must be equal to "8 x 3", i.e., 24.

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>

7 0
2 years ago
In the​ 1970s, due to world​ events, there was a gasoline shortage in the United States. There were often long lines of cars wai
barxatty [35]

Answer:

Part A: The average car length is 9.1 feet to the nearest tenth foot

Part B: The line would be 9100 feet to contained 1000 cars

Step-by-step explanation:

* Lets explain how to solve the problem

# Part A:

- There were 62 cars in a line that stretched 567 feet

- The cars are lined up bumper-to-bumper

- That means there is no empty spaces between the cars

* To find the average length of the car we will divide the length of

  the line by the numbers of the cars

∵ The average car length = length of the line/number of cars

∵ The length of the line is 567 feet

∵ The numbers of the cars is 62 cars

∴ The average car length = 567/62 = 9.1 feet

* The average car length is 9.1 feet to the nearest tenth foot

# Part B:

- There are 1000 cars

- We need to find the length of line which contained the cars

∵ The average car length = length of the line/number of cars

∵ The average of car length is 9.1 feet

∵ The number of the cars is 1000 cars

∴ 9.1 = length of the line/1000

- Multiply both sides by 1000

∴ The length of the line = 9.1 × 1000 = 9100 feet

∴ The line would be 9100 feet to contained 1000 cars

7 0
3 years ago
A blank is a rectangular ​
UNO [17]

Answer:

I would say parallelogram. So the rectangle still fits but more shapes can be applied.

8 0
3 years ago
In the diagram,MNO is a right angled triangle,Mn=13 cm and MN is 5 cm. Find the value of x​
Natali [406]

Answer:12

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
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