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andre [41]
4 years ago
6

Please I just need this one to pass. Please help!!!

Mathematics
1 answer:
Gwar [14]4 years ago
4 0

ASA, HL, and SAS.

AAS wouldn't work, and LA  and LL don't exist

Hope this helps!

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Which shows the following expression after the negative exponents have been eliminated? m^7 n^3/ mn^-1 assume m=0 and n=0
aliina [53]

Given expression is \frac{m^7n^3}{mn^{-1}}.

where m \neq 0, n \neq 0,

Now we have to simplify this and find the next step so that negative exponent gets eliminated.

We know that when negative exponent changes sign, then it moves from numerator to denominator or from denominator to numerator as shown in the formula:

x^{-m}=\frac{1}{x^m}

or\frac{1}{x^{-m}}=x^{m}


n has negative exponent in denominator so it will move to numerator and we get:

\frac{m^7n^3n^1}{m}

or \frac{m^7n^3n}{m}

Hence final answer is \frac{m^7n^3n}{m}.

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3 years ago
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g(6)

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