PLEASE HURRY IT'S URGENT!!!!!

To calculate at what time Jenny will arrive in Rochefort, the first step is to calculate the approximate time of the trip. Now, to calculate this consider the time of a movement (t) equals to the distance (d) divided by the speed (s), the process is shown below:

t = 483 km / 84 km/h

t = 5.75 hours

In this number 5 refers to the hours and 0.75 represents 45 minutes considering 0.75 x 60 minutes in one hour = 45 minutes. Therefore, the total time from Paris to Rochefort is 5 hours and 45 minutes. Now, to calculate the time of arrival add this result to the time of departure.

Add the hours: 5 hours + 9 hours: 14 hours

Add the minutes: 50 minutes + 45 minutes =95 minutes

95 minutes are equivalent to 1 hour (60) minutes and 35 minutes

Calculate the total

Hours: 14 hours + 1 hour = 15 hours or 3 in the 12 hour system (15 hours - 12 hours = 3 p.m.)

Minutes: 35 minutes

4 0

3 years ago

Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$