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Bas_tet [7]
3 years ago
6

PLEASE HURRY IT'S URGENT!!!!!

Mathematics
2 answers:
icang [17]3 years ago
8 0

C. 11/20<4/7

it's the answer

nasty-shy [4]3 years ago
5 0
The answer is C) 11/20<4/7
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Firdavs [7]
The first number is x axis while the second is y

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What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve. mc017-1.jpg and x = 1 mc017-2.jpg and x = –1 mc
Wittaler [7]

We are given equation :x^6+6x^3+5=0

Use\:the\:rational\:root\:theorem

\mathrm{Therefore,\:we\:need\:to\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:5}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

\mathrm{Compute\:}\frac{x^6+6x^3+5}{x+1}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }x^5-x^4+x^3+5x^2-5x+5

Therefore, final factored form it

x^6\:+\:6x^3\:+\:5=\left(x+1\right)\left(x^5-x^4+x^3+5x^2-5x+5\right)

We can't factor it more.

Therefore,

x+1=0.

x=-1.

Therefore, the real solution of the equation would be -1.


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4 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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