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2 years ago

13

Which model shows the correct factorization of x2 – x – 2? Image for option 1 Image for option 2 Image for option 3 Image for op

tion 4

2 answers:

Contact [7]2 years ago

6 0

Hint: Please express exponentiation with the "^" symbol: x^2 - x - 2.

Note that the final term factors to (-2)(-1), and that -2x and +1x combine to produce the middle term, -x. Thus, the factors of this polynomial are

(x+1)(x-2).

Please do not refer to "Image for Option 1," etc., unless you are actually sharing the image!

jok3333 [9.3K]2 years ago

5 0

Image B is the correct answer

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What is the value of the fourth term in a geometric sequence for which a =<br> 110 and r=0.5?

zavuch27 [327]

110(0.5^3)=13.75
The answer is 13.75

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2 years ago

A gross is equal to 144 items. A baker's dozen is equal to

yawa3891 [41]

Answer:

Approximately 11 baker's dozens equal 1 gross.

Step-by-step explanation:

The number of items in a baker's dozen = 13

The gross = 144 items

So, the number of baker's dozen in a gross

= $\frac{\textrm{Total number of items in a gross}}{\textrm{Total number of items on a baker's dozen}}$

= $\frac{144}{13} = 11.07$

Hence, approximately 11 baker's dozens equal 1 gross.

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2 years ago

MATH HELP PLZ!!!

RoseWind [281]

Answer:

a) $tan (157.5) = \frac{1-cos 315}{sin315}$

b)

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

c)

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

d)

cos 330° = 1- 2 sin² (165°)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

By using trigonometry formulas

a)

cos2∝ = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ = 2 cos² ∝/2

$cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}$

b)

cos2∝ = 1- 2 sin² ∝

cos∝ = 1- 2 sin² ∝/2

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

<u><em>Step(i):-</em></u>

Given

$tan\alpha = \frac{sin\alpha }{cos\alpha }$

we know that trigonometry formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

Given

$tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }$

put ∝ = 315

$tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }$

multiply with ' 2 sin (∝/2) both numerator and denominator

$tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2} }{2sin(\frac{315}{2} cos(\frac{315}{2}) }$

Apply formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

now we get

$tan (157.5) = \frac{1-cos 315}{sin315}$

b)

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 330° above formula

$sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}$

$sin^{2} (165) = \frac{1-cos (330) }{2}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

c )

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 315° above formula

$sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

d)

cos∝ = 1- 2 sin² ∝/2

put ∝ = 330°

$cos 330 = 1 - 2sin^{2} (\frac{330}{2} )$

cos 330° = 1- 2 sin² (165°)

3 0

2 years ago

Guys help me on this one please…

Ann [662]

Answer: 6. 35 hours

7. 741 Miles

8. 1.5 or 1.54

Step-by-step explanation:

6. 142.20/6=23.7

829.50/23.7=35

7. 117/3=39

39x19=741

8.19/12.35=1.538

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1 year ago

Find the values of x and y.

olchik [2.2K]

Answer:

value of x = 26

value of y = 26 \|2

( 26 root 2 )

Step-by-step explanation:

here's the solution : -

=》

$\sin(45) = \frac{perpendicular}{hypotenuse}$

=》

$\frac{1}{ \sqrt{2} } = \frac{26}{y}$

=》

$y = 26 \sqrt{2}$

and

$\tan(45) = \frac{perpendicular}{base}$

=》

$1 = \frac{26}{x}$

=》

$x = 26$

8 0

2 years ago