Answer:flow velocity of the water leaving the end of the hose is 31.87 cm/s or 0.3187 m/s
Explanation:
Given that
Diameter of hose, d = 5/8 in
changing to cm becomes
1 inch =2.54 cm
5/ 8 inch=0.625 x 2.54= 1.5875cm
Volume of water filled = 2gallons
changing to cubic centimeters
1 gallon = 3785.41cm^3
2 gallons = 3785.41 x 2 =7570.82cm^3
Time, t = 2 min
60 sec= 1 min
?? sec = 2 min
= 120 secs
The volumetric flow rate of water, F is given as
F = V/t = 7570.82cm^3÷ 120 seconds
F = 63.09 cm^3/s
We Know that The volumetric flow rate is also equal the cross sectional area of pipe times the speed of flow(velocity of flow). ie
F = Av
v = F/A
Since Area A = πd^2/4
v = F/(πd^2/4)
v = 4F/πd^2
Puting the given values;
v = (4× 63.09 )/(π×1.5875²)
v = 252.36/πx 2.5202
v = 31.869 cm/s =31.87cm/s 0r 0.3187m/s
Therefore flow velocity of the water leaving the end of the hose is 31.87 cm/s or 0.3187 m/s
The SI unit of power is the watt<span>, which is equal to one </span>joule/<span>per second.
So I would say Watt is the answer. Hope it helped. :)
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Answer:
L = 1.023 H
Explanation:
given,
radius of the cylindrical solenoid = r = 0.6 m
Number of turns = N = 600
Length = l = 0.5 m
Current in the cylindrical solenoid = 15 A
Inductance in the coil = ?
using formula
L = 1.023 H
the inductance L of the coil is = 1.023 H
The answer is D
This is an example of Newton's third law of motion.
The active force is the fish against the water, so the reactive force would be the reverse, the equal force of the water on the fish.