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HACTEHA [7]
2 years ago
10

A 150kg motorcycle starts from rest and accelerates at a constant rate along with a distance of 350m. The applied force is 250N

and the coefficient of kinetic friction is 0.03. What is the net force applied to the motorcycle?
Physics
1 answer:
mart [117]2 years ago
3 0

Answer:

205N

Explanation:

The net force (F) is the difference between the applied force(F_{A}) and the kinetic frictional force(F_{R}). i.e

F = F_{A} - F_{R}    -----------------(i)

Note that;

F_{R} = μmg

Where;

μ = coefficient of kinetic friction

m = mass of the body

g = acceleration due to gravity = 10m/s²

Equation (i) then becomes;

F = F_{A} - μmg        -------------------(ii)

<em>Given from question;</em>

m = mass of motorcycle = 150kg

μ = 0.03

F_{A} = 250N

Substitute these values into equation (ii) as follows;

F = 250 - (0.03 x 150 x 10)

F = 250 - (45)

F = 205N

Therefore, the net force applied to the motorcycle is 205N

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olasank [31]

Answer:

Power, P = 30 W

Explanation:

We have,

Voltage drop of a circuit is 60 V

Resistance of the resistor is 120 ohms

Current across the circuit is 0.5 A

It is required to find the power conducted by the resistor. Power conducted by a resistor is given by :

P=VI

V and I are voltage and current

P=60\times 0.5\\\\P=30\ W

So, the power conducted by the resistor is 30 watts.

3 0
2 years ago
A 59kg child starting from rest slides down a water slide with a vertical height of 5.0m. what is the child's speed halfway down
KIM [24]
<span>EP (potential energy) = mgy -> (59)(9.8)(-5) = -2,891
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   EK = 0.5mv^2, but can also be v = sqrt(2EK/m).
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6 0
3 years ago
Two vectors are given by a = 8.6i + 5.1 j and b = 931 + 9.5.
skelet666 [1.2K]

Answer:

<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong):</em>

a) a×b = 34.27k

b) a·b = 128.43

c) (a + b)·b = 305.17

d) The component of a along the direction of b = 9.66

Explanation:

<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong)</em> we can proceed as follows:  

a) The vectorial product, a×b  is:

a \times b = (8.6*9.5 - 5.1*9.3)k = 34.27k

b) The escalar product a·b is:

a\cdot b = (8.6*9.3) + (5.1*9.5) = 128.43

c) <u>Asumming (a</u><u> </u><u>+ b)·b</u> <em>instead a+b·b</em> we have:

(a + b)\cdot b = [(8.6 + 9.3)i + (5.1 + 9.5)j]\cdot (9.3i + 9.5j) = (17.9i + 14.6j)\cdot (9.3i + 9.5j) = 305.17

d) The component of a along the direction of b is:

a*cos(\theta) = \frac{a\cdot b}{|b|} = \frac{128.43}{\sqrt{9.3^{2} + 9.5^{2}}} = 9.66

I hope it helps you!                        

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Answer:

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2 years ago
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mario62 [17]

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It may or may not be effective, and it may or may not even be
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its practices are based on hearsay, and have not been subjected
to scientific methods of investigation and evaluation.

<span />
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