Answer:
0.67 m/s²
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 0 m/s
Final velocity (v) = 2 m/s
Time (t) = 3 secs
Acceleration (a) =?
Acceleration can be defined as the rate of change of velocity with time. It can be represented mathematically as:
Acceleration = change in velocity /time.
a = (v – u) /t
With the above formula, we can calculate the acceleration of the lift as shown below:
Initial velocity (u) = 0 m/s
Final velocity (v) = 2 m/s
Time (t) = 3 secs
Acceleration (a) =?
a = (v – u) /t
a = (2 – 0) /3
a = 2/3
a = 0.67 m/s²
Thus, the acceleration of the lift between 0 and A is 0.67 m/s².
Answer:
0.00034 m
Explanation:
Since the length of the aluminium bar, L is given by , L = 1.0000 + 2.4 × 10⁻⁵T and T = 14.1°C, we substitute the value of T into L. So, we have L = 1.0000 + 2.4 × 10⁻⁵ × 14.1°C = 1.0000 + 0.0003384 = 1.0003384 m. The change in length is thus 1.0003384 - 1.0000 = 0.0003384 m ≅ 0.00034 m
The answer would be: B
Hope tis helps!
Answer:
The atoms start vibrating really fast, making the space between them larger. It's an increase in Kinetic Energy.