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prisoha [69]
3 years ago
13

What is the reactive force when a fish swims through water?

Physics
1 answer:
natima [27]3 years ago
7 0
The answer is D

This is an example of Newton's third law of motion.

The active force is the fish against the water, so the reactive force would be the reverse, the equal force of the water on the fish.
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A bicycle rider traveling east at 10 km/hr sees a blue car pass her appearing to travel west at 50 km/hr. What is the blue car's
BigorU [14]

Answer:

v_{bR} = 25 km/h towards west

Explanation:

As we know that the speed of the blue car as appear to the bicycle rider is given as

v_{bc} = 50 km/h towards west

also it is given that bicycle is moving at speed of 10 km/h towards East

so here we have

v_{bc} = v_b - v_c

so we have

v_b = v_{bc} + v_c

v_b = -50 + 10 = 40 km/h towards west

now speed of the red car is given as 15 km/h towards west

so here the relative speed of blue car with respect to red car is given as

v_{bR} = v_b - v_R

v_{bR} = 40 - 15 = 25 km/h towards west

8 0
3 years ago
Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27
densk [106]

Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

\rho=n\times\dfrac{m}{V_{c}\times N_{A}}

n=\dfrac{\rho\timesV_{c}\times N}{m}....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

\rho=\dfrac{1}{\dfrac{12.5}{4.27}+\dfrac{87.5}{6.35}}\times100

\rho=5.98

We calculate the mass of the alloy

m=\dfrac{1}{\dfrac{12.5}{61.4}+\dfrac{87.5}{125.7}}\times100

m=111.15

Put the value into the equation (I)

n=\dfrac{5.9855\times(0.395\times10^{-9}\times10^{2})^3\times6.023\times10^{23}}{111.15}

n=1.99\approx 2\ atoms/cell

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

5 0
3 years ago
I don’t understand I need help asap
hammer [34]
For the first question, you got them right, for the two you left blank, initial(beginning) velocity: 2 m/s the final velocity is: 12 m/s
3 0
3 years ago
What happens to electric charges within a conductor when a charged object is brought close to it
Agata [3.3K]
Well, if a charger conductor is touched to another object or close enough to touching the object then the conductor can transfer its charge to that object. Conductors allow for electrons to be transported from particle to particle, so a charged object will always distribute its charge until the repulsive forces are minimized.
8 0
3 years ago
Joanna wants to determine the speed of sound in xenon. When she plays a tone with a frequency of 440 Hz, the resulting sound wav
iVinArrow [24]

The speed of the sound in the xenon is 178 m/s. And the right option is b 178 m/s

<h3 /><h3>What is speed?</h3>

Speed can be defined as the ratio of the total distance traveled by a body to the total time taken.

To calculate the speed of the sound in the xenon, we use the formula below.

Formula:

  • v = λf............. Equation 1

Where:

  • v = Speed of the sound in xenon
  • f = Frequency
  • λ = Wavelength.

From the question,

Given:

  • f = 440 Hz
  • λ = 40.4 cm = 0.404 m

Substitute the values above into equation 1

  • v = 440(0.404)
  • v = 177.76 m/s.
  • v ≈ 178 m/s

Hence, The speed of the sound in the xenon is 178 m/s. And the right option is b 178 m/s

Learn more about speed here: brainly.com/question/4931057

7 0
2 years ago
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