What is the period of oscillation of a mass 40kg on a spring with constant k=10N/m?
1 answer:
The period of oscillation of the system is 12.56 s
Explanation:
The period of oscillation of a spring-mass system is given by
where
m is the mass attached to the spring
k is the spring constant
For the system in this problem, we have
m = 40 kg
k = 10 N/m
Substituting into the equation, we find
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Answer:
0.47 N
Explanation:
Here we have a ball in motion along a circular track.
For an object in circular motion, there is a force that "pulls" the object towards the centre of the circle, and this force is responsible for keeping the object in circular motion.
This force is called centripetal force, and its magnitude is given by:
where
m is the mass of the object
is the angular velocity
r is the radius of the circle
For the ball in this problem we have:
m = 40 g = 0.04 kg is the mass of the ball
is the angular velocity
r = 30 cm = 0.30 m is the radius of the circle
Substituting, we find the force:
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We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.
There is NO initial vertical velocity, so:
Rearrange to solve for time:
Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)
Now, use the following for finding the HORIZONTAL distance using its horizontal velocity: