What is the period of oscillation of a mass 40kg on a spring with constant k=10N/m?
1 answer:
The period of oscillation of the system is 12.56 s
Explanation:
The period of oscillation of a spring-mass system is given by
where
m is the mass attached to the spring
k is the spring constant
For the system in this problem, we have
m = 40 kg
k = 10 N/m
Substituting into the equation, we find
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Answer:
α = 1930.2 rad/s²
Explanation:
The angular acceleration can be found by using the third equation of motion:
where,
α = angular acceleration = ?
θ = angular displacement = (1500 rev)(2π rad/1 rev) = 9424.78 rad
ωf = final angular speed = 0 rad/s
ωi = initial angular speed = (960 rev/s)(2π rad/1 rev) = 6031.87 rad/s
Therefore,
<u>α = - 1930.2 rad/s²</u>
<u>negative sign shows deceleration</u>