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Gelneren [198K]

3 years ago

15

What is the period of oscillation of a mass 40kg on a spring with constant k=10N/m?

1 answer:

iVinArrow [24]3 years ago

7 0

The period of oscillation of the system is 12.56 s

Explanation:

The period of oscillation of a spring-mass system is given by

$T=2\pi \sqrt{\frac{m}{k}}$

where

m is the mass attached to the spring

k is the spring constant

For the system in this problem, we have

m = 40 kg

k = 10 N/m

Substituting into the equation, we find

$T=2\pi \sqrt{\frac{40}{10}}=12.56 s$

#LearnwithBrainly

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Answer:

The time it takes for 14C to radioactively decay is described by its half-life. C has a half-life of 5,730 years. In other words, after 5,730 years, only half of the original amount of 14C remains in a sample of organic material. After an additional 5,730 years–or 11,460 years total–only a quarter of the 14C remains.

Explanation:

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2 years ago

A 8 g object displaces 50ml of water, what is its specific gravity?

Igoryamba

Answer:

8.3

Explanation:

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2 years ago

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What is the wavelength in nm of a light whose first order bright band forms a diffraction angle of 30 degrees, and the diffracti

Artist 52 [7]

Answer:

The wavelength is 3500 nm.

Explanation:

d= $\frac{1}{700 lines per mm} = 0.007mm = 7000 nm$

n= 1

θ= 30°

λ= unknown

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d sinθ = nλ

λ = $\frac{7000 nm sin 30}{1}$

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8 0

3 years ago

a ball of 5 kg is moving towards the wall at 6 m/s. after a while, it hits the wall and rebounds back at 4 m/s in the opposite d

iris [78.8K]

Answer:-50 J

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3 0

3 years ago

A car and a lorry are about to collide. When they collide the two vehicles become tightly locked together. The lorry is going at

BartSMP [9]

Answer:

The speed of the vehicles immediately after the collision is 5.84 m/s.

Explanation:

The speed of the vehicles after the collision can be found by conservation of linear momentum:

$p_{i} = p_{f}$

$m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}$

Where:

m₁: is the mass of the car = 0.5 ton = 500 kg

m₂: is the mass of the lorry = 9.5 ton = 9500 kg

$v_{1_{i}}$ : is the initial speed of the car = 40 km/h = 11.11 m/s

$v_{2_{i}}$ : is the initial speed of the lorry = 20 km/h = 5.56 m/s

$v_{1_{f}}$ : is the final speed of the car =?

$v_{2_{f}}$ : is the final speed of the lorry =?

Since the two vehicles become tightly locked together after the collision $v_{1_{f}}$ = $v_{2_{f}}$ :

$m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = v(m_{1} + m_{2})$

$v = \frac{m_{1}v_{1_{i}} + m_{2}v_{2_{i}}}{m_{1} + m_{2}} = \frac{500 kg*11.11 m/s + 9500 kg*5.56 m/s}{500 kg + 9500 kg} = 5.84 m/s$

Therefore, the speed of the vehicles immediately after the collision is 5.84 m/s.

I hope it helps you!

8 0

2 years ago