Answer:
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The statement which best described the effect of color on energy absorption and reflection is this: LIGHT COLORS REFLECT MORE AND ABSORB LESS THAN DARK COLORS. Black color absorbs all incident radiations while white color reflects all incident radiations; all other colors fall in the midst of these two colors.
Answer:
T = 215.33 °C
Explanation:
The activation energy is given by the Arrhenius equation:
<u>Where:</u>
k: is the rate constant
A: is the frequency factor
Ea: is the activation energy
R: is the gas constant = 8.314 J/(K*mol)
T: is the temperature
We have for the uncatalyzed reaction:
Ea₁ = 70 kJ/mol
And for the catalyzed reaction:
Ea₂ = 42 kJ/mol
T₂ = 20 °C = 293 K
The frequency factor A is constant and the initial concentrations are the same.
Since the rate of the uncatalyzed reaction (k₁) is equal to the rate of the catalyzed reaction (k₂), we have:
(1)
By solving equation (1) for T₁ we have:
Therefore, we need to heat the solution at 215.33 °C so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction.
I hope it helps you!
Answer:
Disnt make sense show me question
Answer: 8 moles
Explanation:
C3H8(g) + 5O2(g) ---> 3CO2(g) + 4H2O(g)
The balanced equation above shows the combustion of propane, C3H8 (for x is 3; y is 8) in oxygen, O2 to yield carbon dioxide, CO2 and water, H2O
The mole ratio on combustion are as follows:
5 moles of O2 react to produce 3 moles of CO2
Z mole of O2 react to produce 4.8 moles of CO2
To get the value of Z, cross multiply
4.8 moles x 5 mole = 3 mole x Z
24 = 3Z
Divide both sides by 3
24/3 = 3Z/3
8 = Z
Thus, in the combustion of propane, 8 moles of oxygen (O2) are needed to react to produce 4.8 moles of carbon dioxide (CO2)
