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lesantik [10]
3 years ago
11

What is the radius?

Chemistry
1 answer:
slavikrds [6]3 years ago
3 0
The radius is the distance to cover
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Draw the best lewis structure for h 2 ​ co 3 ​ and calculate the formal charge on carbon.
schepotkina [342]
The Lewis structure of Carbonic Acid (H₂CO₃) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with hydroxyl groups.

Formal Charge;
                        Formal charge is caculated as,

Formal charge  =  # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]

Formal charge on Carbon;

Formal charge  =  4 - [ 0 + 8/2]

Formal charge  =  4 - [4]

Formal charge  =  Zero

7 0
3 years ago
PLS HELP! Suppose you have a sample of an unknown mineral with a mass of 86 g. You place the sample in a graduated cylinder fill
bija089 [108]
O le elo ma muli pipilo ma le kaoga e fai gi o meaoga
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3 years ago
Which of the following forces is responsible for accretion?
Makovka662 [10]

Answer:

It's explained by nebular theory, which describes the forces and processes at play as a nebula spins and accretes into a star and its planets orbiting it. A key piece of information to always keep in mind is that the force of gravity is responsible for accretion and all the objects it forms.

Explanation:

I hope this helps my mom helped me with this question too

8 0
3 years ago
1)CH<br>2<br>C = CHCH,how many pi and sigma bonds are present in this compound?<br>​
Vedmedyk [2.9K]

Answer:

1 pi bond and 6 sigma bonds

5 0
3 years ago
What is the mass present in a 10.0L container of oxygen at a pressure of 105kPa and 20 degrees Celsius
omeli [17]

1.31 × 10⁴ grams.

<h3>Explanation</h3>

Assume that oxygen acts like an ideal gas. In other words, assume that the oxygen here satisfies the ideal gas law:

P \cdot V = n \cdot R\cdot T,

where

  • P the pressure on the gas, \bf P = 10^{5}\;\textbf{kPa}=10^{8}\;\textbf{Pa};
  • V the volume of the gas, V = 10.0 \;\text{L} = 10.0\times 10^{-3}\;\text{m}^{3}=10^{-2}\;\text{m}^{3};
  • n the number of moles of the gas, which needs to be found;
  • T the absolute temperature of the gas, T=20\;\textdegree{}\text{C} = (20 + 273.15)\;\text{K} = 293.15\;\text{K}.
  • R the ideal gas constant, R = 8.314 if P, V, and T are in their corresponding SI units: Pa, m³, and K.

Apply the ideal gas law to find n:

n = \dfrac{P\cdot V}{R\cdot T} = \dfrac{{\bf 10^{8}\;\textbf{Pa}}\times 10^{-2}\;\text{m}^{3}}{8.314 \;\text{Pa}\cdot\text{m}^{3}\cdot\text{K}^{-1}\cdot\text{mol}^{-1}\times 293.15\;\text{K}} = 410.3\;\text{mol}.

In other words, there are 410.3 moles of O₂ molecules in that container.

There are two oxygen atoms in each O₂ molecules. The mass of mole of O₂ molecules will be {\bf 2}\times 16.00 = 32.00\;\text{g}. The mass of 410.3 moles of O₂ will be:

410.3 \times 32.00 = 1.31\times10^{4}\;\text{g}.

What would be the mass of oxygen in the container if the pressure is approximately the same as STP at 10^{5}\;\textbf{Pa} or  10^{2}\;\text{kPa} instead?

6 0
4 years ago
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