How much water must be removed by steam distillation to recover this natural product from 3.0 g of a spice that contains 10% of
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Answer:
a) Mass of solution is 16,605 milli grams.
b) 57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.
c) 1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.
Explanation:
Mass by mass percentage of calcium chloride solution, wt% = 12.0%
Density of the solution = d = 1.107 g/mL
a) Volume of the solution , V= 15.0 mL
Mass of the solution = m
Mass of solution = 16.605 g = 16,605 mg (1g = 1000 mg)
b) Mass of the solution = m
Volume of the solution = V = 431.3 mL
Mass of calcium chloride = x
w% = 12.0%
57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.
c) Moles of calcium chloride =
V = Volume of the solution in Liters
n = 0.5161 mole
V = 431.3 mL = 0.4313 L
1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.