2. Stanford–Binet IQ Test scores are normally distributed with a mean score of 100 and a standard deviation of 15. a. Sketch the
distribution of Stanford–Binet IQ test scores. b. Write the equation that gives the z score corresponding to a Stanford–Binet IQ test score. Sketch the distribution of such z scores. c. Find the probability that a randomly selected person has an IQ test score i. Over 145. ii. Under 91
1 answer:
Answer:
0.0010,0.2743
Step-by-step explanation:
Given that Stanford–Binet IQ Test scores are normally distributed with a mean score of 100 and a standard deviation of 15
If x represents the scores then
X is N(100,15)
a) See enclosed file
b) Z score =
c) the probability that a randomly selected person has an IQ test score
i. Over 145.
=
ii. Under 91
=
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From my own solution, my answer is closest to D<span>. 1951 yd; 27°
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The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>
Pls. see my attachment.
In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite
From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.
I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.
Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.
With regards to the angle of depression, I used this formula:
tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14</span>°<span>
</span>
</span><span>
The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>
Pls. see my attachment.
In it I divided the big triangle into two small right triangles.
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite
From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.
I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle.
Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.
With regards to the angle of depression, I used this formula:
tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14</span>°<span>
</span>