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ruslelena [56]
3 years ago
6

Matrice question please help!

Mathematics
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

you have simply written 2 matrices in the picture. Tell me which operation do you want to apply on these rectangular matrices

Step-by-step explanation:

You might be interested in
F(x) = x^2+1 and g(x) = x-4 <br> (f/g)(5)=
Nezavi [6.7K]

The value of the composite function is (f/g)(5)= 26

<h3>How to evaluate the composite function?</h3>

The functions are given as:

f(x) = x^2+1 and g(x) = x-4

To calculate the composite function, we use the following formula

(f/g)(x)= f(x)/g(x)

So, we have:

(f/g)(5)= f(5)/g(5)

Calculate f(5) and g(5)

f(5) = 5^2+1 and g(5) = 5-4

This gives

f(5) = 26 and g(5) = 1

Substitute f(5) = 26 and g(5) = 1 in (f/g)(5)= f(5)/g(5)

(f/g)(5)= 26/1

Evaluate

(f/g)(5)= 26

Hence, the value of the composite function is (f/g)(5)= 26

Read more about composite function at

brainly.com/question/10687170

#SPJ1

7 0
2 years ago
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
3 years ago
Im confused can somebody help me please
ivann1987 [24]

well, we know the piece-wise function is f(x)= \begin{cases} 7x+10&x < 0\\\\ 7x+20&x\geqslant 0 \end{cases}

hmmm so what's f(-1), namely what is f(x) when x = -1?

well, when x = -1, hmm -1 is less than 0, so the subfunction that applies to that will be when "x" is less than 0, namely the part of 7x + 10, so we can say

f(-1) = 7(-1) + 10

f(-1) = 3

so hmm what's f(0) or namely, what's f(x) when x = 0?

well, what subfunction applies when x = 0? well, it has to be the subfunction with "x greater or <u>equals</u> to 0", x ⩾ 0, so then is 7x + 20

f(0) = 7(0) + 20

f(0) = 20.

6 0
2 years ago
Solve the formula ..........
Flauer [41]
D=rt for t
÷r both sides
d/r=t
A
3 0
3 years ago
three of the names do not belong in this box. cross them out. write the name of the number on the top box.
mario62 [17]

Answer:

the number is 12

Step-by-step explanation:

20 - 7, 40 - 23, and 4 x 4

3 0
3 years ago
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