we can see that the center is (-3, 3) and the radius is 9 units.
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How to find the center and radius of the circle?</h3>
The general circle equation, for a circle with a center (a, b) and radius R is given by:
(x - a)^2 + (y - b)^2 = R^2
Here we have the equation:
x^2 + y^2 + 6x = 6y + 63
Let's complete squares:
x^2 + y^2 + 6x - 6y = 63
(x^2 + 6x) + (y^2 - 6y) = 63
(x^2 + 2*3x) + (y^2 - 2*3y) = 63
Now we can add and subtract 9, (two times) so we get:
(x^2 + 2*3x + 9) - 9 + (x^2 - 2*3x + 9) - 9 = 63
(x + 3)^2 + (y - 3)^2 = 63 + 9 + 9 = 81 = 9^2
(x + 3)^2 + (y - 3)^2 = 9^2
Comparing with the general circle equation, we can see that the center is (-3, 3) and the radius is 9 units.
If you want to learn more about circles:
brainly.com/question/1559324
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Step-by-step explanation: To estimate the value of the square root of 59, we know that the square root of 49 is 7 and the square root of 64 is 8. This means that the square root of 59 must have a value between 7 and 8.
Answer:
12.5%
Step-by-step explanation:
Five divided by 40 is 12.5
9514 1404 393
Answer:
K(-14 1/3, -34 2/3)
Step-by-step explanation:
The division ratio says ...
(L -J)/(K -L) = 3/2
2(L -J) = 3(K -L)
5L -2J = 3K
K = (5L -2J)/3
K = (5(-15, -20) -2(-16, 2))/3 = (-75+32, -100-4)/3 = (-43/3, -104/3)
K = (-14 1/3, -34 2/3)
