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3 years ago

Which graph represents the same relation as the rule y = 2x, for all real numbers x?

Mathematics

1 answer:

olga_2 [115]3 years ago

7 0

Answer:

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Step-by-step explanation:

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What is the value of x in the equation below?

belka [17]

$remember$
$ln(a^b)=bln(a)$
$ln(e)=1$
$so$
$ln(e^x)=xln(e)=x$

$1+2e^{x+1}=9$
$minus \space\ 1 \space\ both \space\ sides$
$2e^{x+1}=8$
$divide \space\ both \space\ sides \space\ by \space\ 2$
$e^{x+1}=4$
$take \space\ ln \space\ of \space\ both \space\ sides$
$ln(e^{x+1})=ln(4)$
$(x+1)ln(e)=ln(4)$
$x+1=ln(4)$
$minus \space\ 1 \space\ from \space\ both \space\ sides$
$x=ln(4)-1$
$answer \space\ is \space\ C=ln(4)-1$

5 0

3 years ago

Read 2 more answers

Using the slope and the y intercept, graph the line represented by the following equation.

PtichkaEL [24]

Beforehand let me apologize for my sloppy handwriting. I'm a lefty, so please deal with me. . Anyway, the equation you listed didn't really have a x, because a linear equation is y= mx+b, and anything with x is the slope. But I did see y and a number on one side, so I'm like maybe I can get these two alone. So here's what I did:

2y + 4=0
-4 -4 I subtracted 4 on both sides. Why because you would want "y" alone.
Next,
2y= -4
Now to get "y" alone you want to divide on both sides.
2y= -4/ 2
y= -2
Now you're probably thinking "how do you graph it? There's no "x" in the equation." Well, you just graph it. Since the answer is y= -2, you go to the y axis, look for -2, and place a line to indicate that is the equation. And to make it clear, remember y is the y-intercept.

I really do hope this helps you, if not message me. I'll be happy to help, and again I'm sorry for my handwriting!

4 0

2 years ago

Read 2 more answers

If a club charges dues of $200 a year, it will have 50 members. For each $5 it raises its dues, it loses a member. USE AN EQUATI

Vikentia [17]

Answer:

The value is $y = \$ 225$

Step-by-step explanation:

From the question we are told that

The amount charge per year is $k = \$ 200$

The number of members it will have at this amount is $n = 50$

The amount amount increase that will lead to the loss of a single member is $z = \$ 5$

Generally the total amount the club would obtain from its members is mathematically represented as

$I = Amount \ due\ paid * Number \ of members$

Now let x denote the number of member lost

Hence

$I = (k + zx) (n-x )$

=> $I = (200 + 5x) (50-x )$

=> $I = 10000+50x-5x^2$

Thus the number of members that be removed to give the maximum income from dues is obtained by differentiating the above equation and equating it to zero

$\frac{dI}{dx} = 50-10x$