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leonid [27]
3 years ago
12

Write an equation for the nth term of the arithmetic sequence.

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0

Answer:

<h3>              \bold{a_n=6n-3}\\\\\bold{a_{50}=297} </h3>

Step-by-step explanation:

3, 9, 15, 21,  ...

9-3 = 6;   15-9 = 6;   21-15 = 6   ⇒  d = 6

first term:  a = 3

difference:  d = 6

so the formula:

                         a_n=a+d(n-1)\\\\a_n=69+6(n-1)\\\\a_n =3+6n-6\\\\\underline{a_n=6n-3}                        

and:

   a_{50}=6\cdot50-3=300-3=297

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When will n(A∩B)=0? Explain and give an example.
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Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step
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Answer:

Jada should have multiplied both sides of the equation by 108.

Step-by-step explanation:

The question is incomplete. Find the complete question in the comment section.

Given the equation -4/9 = x/108, in order to determine Jada's error, we need to solve in our own way as shown:

Step 1: Multiply both sides of the equation by -9/4 as shown:

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1 = -9x/432

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Cross multiplying

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Multiply both sides by 108 to have:

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