Start by writing out molar mass of each component:
1) NaOH= 22.99+16+1.01 --> 40
2) Na₃PO₄= (22.99)3 + 94.97 + 64 --> 227.94
3) NaNO₃= 22.99 + 14 + 48 --> 84.99
Now compare the mass of sodium with the rest of the substances:
1) (22.99/40)100%= 57.475%
2) (68.97/227.94)/100%= 30.25%
3) (22.99/84.99)/100%= 27.05%
As seen, the ordered list is: Sodium hydroxide, sodium phosphate and sodium nitrate.
Hope I helped :)
I’m just letting you know this is really easy you just calculate the molar mass of each compound and divide the amount of the compound (grams) by the molecular Mass
The correct answer is Ozone.
Ozone, sometimes known as O3, is a poisonous and unstable gas. Ozone is a potent allotrope of oxygen; it absorbs heat when it is present in large quantities all over the earth. A molecule called ozone has three oxygen atoms in it. At ground level, it is dangerous and unstable. O3 O3's efficacy in treating infections, wounds, and several disorders has been extensively established. Before the turn of the century, it was employed to sterilize drinking water. One study found that ozone could cure 114 different ailments. Headaches, coughing, a dry throat, difficulty breathing, a heavy feeling in the chest, and fluid in the lungs can all be side effects of ozone exposure.
Learn more about Ozone Here :-
brainly.com/question/14330630
#SPJ4
Answer:
66.7%
Explanation:
The reaction for the titration of the excess ferrous ion is:
- 5Fe⁺² + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O
We calculate the moles of Fe⁺² from the used moles of KMnO₄:
- 0.02 M * 15.0 mL = 0.30 mmol KMnO₄
- 0.3 mmol KMnO₄ *
= 1.5 mmol Fe⁺²
Then we substract those 0.30 mmol from the original amount used:
- 0.1 M * 50.0 mL = 5.0 mmol Fe⁺²
- 5.0 - 1.5 = 3.5 mmol Fe⁺²
The reaction between ferrous ammonium sulfate and MnO₂ is:
- 2Fe⁺² + MnO₂ + 4H⁺ → 2Fe³⁺ + Mn²⁺ + 2H₂O
So we convert those 3.5 mmol Fe⁺² that were used in this reaction to MnO₂ moles:
- 3.5 mmol Fe⁺² *
= 1.75 mmol MnO₂
Then we convert MnO₂ to Mn₃O₄, using the reaction:
- 1.75 mmol MnO₂ *
= 0.583 mmol Mn₃O₄
Finally we convert Mn₃O₄ moles to grams:
- 0.583 mmol Mn₃O₄ * 228.82 mg/mmol = 133.40 mg Mn₃O₄
And calculate the percent
- 133.40 / 200 * 100% = 66.7%
