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3 years ago

What mass (g) of ammonium acetate contains 8.334 x 1024 hydrogen atoms?

Chemistry

1 answer:

bezimeni [28]3 years ago

7 0

Answer:

152.4 g

Explanation:

Step 1: Given data

Number of H atoms: 8.334 × 10²⁴ atoms

Step 2: Calculate the moles of H corresponding to 8.334 × 10²⁴ atoms of H

We will use Avogadro's number, that is, there are 6.022 × 10²³ atoms of H in 1 mole of H.

8.334 × 10²⁴ atom × (1 mol/6.022 × 10²³ atom) = 13.84 mol

Step 3: Calculate the moles of ammonium acetate (NH₄CH₃CO₂) that contain 13.84 moles of H

The molar ratio of NH₄CH₃CO₂ to H is 1:7. The moles of NH₄CH₃CO₂ that contain 13.84 moles of H are 1/7 × 13.84 mol = 1.977 mol.

Step 4: Calculate the mass corresponding to 1.977 moles of NH₄CH₃CO₂

The molar mass of NH₄CH₃CO₂ is 77.08 g/mol.

1.977 mol × 77.08 g/mol = 152.4 g

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Shkiper50 [21]

Answer:

pH = 12.52

Explanation:

Given that,

The [H+] concentration is $3\times 10^{-13}$ .

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2 years ago

What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.

AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

$pH=pK_{a} + log(\frac{[Base]}{[Acid]})$

According to the given conditions, the equation will become as follow

$pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})$

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

$pH=6.86 + log(\frac{0.058}{0.042})$

$pH=7.00$

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