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Yuri [45]
3 years ago
7

Would Cl2 be reduced by I- ? Explain.

Chemistry
2 answers:
Cerrena [4.2K]3 years ago
7 0
Yes. Cl has a is more electronegative than the iodide ion and thus attracts electrons more strongly than the iodide ion.

This is mainly due to the fact that chlorine has only 3 shells, compared to iodides 4 shells. This means a greater electrostatic attraction force exists between the chlorine nucleus and the outer electron than iodide and its outer electrons. As a result the Chlorine will be reduced to Cl- and iodide will be oxidised to iodine, as it will have lost its electron to the chlorine. 

The equation is 
Cl2 + 2I-  --> 2Cl- + I2 


anzhelika [568]3 years ago
4 0

Answer:

Yes, and it would yield gaseous iodine and chloride ions.

Explanation:

Hello,

In this case, when gaseous iodine reacts with iodide ions, the reaction results:

Cl_2+I^-\rightarrow I_2+Cl^-

In such a way, by balancing the reaction we obtain:

Cl_2+2I^-\rightarrow I_2+2Cl^-

Therefore, gaseous chlorine would be reduced by iodide ions yielding gaseous iodine and chloride ions.

Best regards.

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Answer:

There is on reason why...

Explanation:

This is one reason astronomers and other scientists use scientific notation when working with very large or very small numbers. Scientific notation is a system for writing and working with numbers that makes it much easier to deal with numbers that are very small or very large.

There you go your awnser

8 0
3 years ago
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The gas CO2 is diffusing at steady state through a tube 0.20 meters long. The tube has a diameter of 0.01 meters and also contai
Serggg [28]

Answer:

The value is J = 1.71 *10^{-6} \ kmol/m^2\cdot s

Explanation:

From the question we are told that

The length the tube is l  =  0.20 \  m

The diameter of the tube is d =  0.01 \  m

The total pressure inside the tube is P  =  101.32\ kPa  =   101.32 *10^{3} \  Pa

The partial pressure of CO2 at the first end is P_1 =  456 \  mmHg  = 456 *133.322 =  60794.832 \  Pa

The partial pressure of CO2 at the other end is P_2 =   76 \  mmHg  =  76 *133 =  10132.472 \  Pa

The temperature is T = 298 K

The diffusion coefficient is D_{1,2} = 1.67 * 10^{-5} \ m^2 /s

Generally the molar flux of CO2 is mathematically represented as

J = \frac{D_{1,2} *  [P_1 -P_2]}{R* T[l]}

Here R is the gas constant with value R =  8.314 \  J/k mol

So

J = \frac{ 1.67 * 10^{-5} *  [60794.832  -10132.472 ]}{8.314  * 298 [0.20]}

J = 1.71 *10^{-3} \ mol/m^2\cdot s

Converting to kmol

        J = \frac{1.71 *10^{-3}}{1000}

        J = 1.71 *10^{-6} \ kmol/m^2\cdot s

         

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Answer:

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3 years ago
7.26 of a hydrate, Cu(NO3)2.xH2O, formed 2.4 g copper(II) oxide.
goldfiish [28.3K]

Number of moles= mass/ molar mass

Or n=m/MM

n = number of moles

m = mass

MM = molar mass

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