Answer:
a) Binomial distribution B(n=12,p=0.01)
b) P=0.007
c) P=0.999924
d) P=0.366
Step-by-step explanation:
a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.
b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.
Then,
c) In this case, the distribution is B(1200,0.01)
d) In this case, the distribution is B(100,0.01)
We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.
950 x 13 /100 x 120/365 = $ 40.60. Hope that's helpful.
The range of the following relation R {(3, −2), (1, 2), (−1, −4), (−1, 2)} is Your answer: {−1, 1, 3} {−1, −1, 1, 3} {−4, −2, 2,
nalin [4]
Answer:
The range is all the y values.
Therefore, the range is : {-4,-2,2}.....I realize choice c has all the y values listed, however, if u have repeating y values, u only have to list it once.
Step-by-step explanation:
Answer:
Hi how are you doing today Jasmine
Answer:
D
Step-by-step explanation:
(f • g)(x)
= f(x) × g(x)
= (x + 4)(3x² - 7)
each term in the second factor is multiplied by each term in the first factor , that is
x(3x² - 7) + 4(3x² - 7) ← distribute both parenthesis
= 3x³ - 7x + 12x² - 28
= 3x³ + 12x² - 7x - 28 ← in standard form
