All categories

3 years ago

2. What conjecture can you make about the eighteenth term in the pattern A, B, A, C, A, B, A, C?

Mathematics

1 answer:

slamgirl [31]3 years ago

4 0

Answer:

The eighteenth term is B

Step-by-step explanation:

I could just write the pattern A B A C out until you get to the eighteenth term

A(1) B(2) A(3) C(4) A(5) B(6) A(7) C(8) A(9) B(10) A(11) C(12) A(13) B(14) A(15) C(16) A(17) B(18)

You might be interested in

A geometric sequence is defined by the equation an = (3)3 − n.

Delvig [45]

PART A

The geometric sequence is defined by the equation

$a_{n}=3^{3-n}$

To find the first three terms, we put n=1,2,3

When n=1,

$a_{1}=3^{3-1}$

$a_{1}=3^{2}$

$a_{1}=9$
When n=2,

$a_{2}=3^{3-2}$
$a_{2}=3^{1}$

$a_{2}=3$

When n=3

$a_{3}=3^{3-3}$

$a_{3}=3^{0}$
$a_{1}=1$
The first three terms are,

$9,3,1$

PART B

The common ratio can be found using any two consecutive terms.

The common ratio is given by,
$r= \frac{a_{2}}{a_{1}}$
$r = \frac{3}{9}$

$r = \frac{1}{3}$

PART C

To find
$a_{11}$

We substitute n=11 into the equation of the geometric sequence.

$a_{11} = {3}^{3 - 11}$

This implies that,

$a_{11} = {3}^{ - 8}$

$a_{11} = \frac{1}{ {3}^{8} }$

$a_{11}=\frac{1}{6561}$

4 0

3 years ago

¿Cuáles son los números primos entre 2 y 20?

Rus_ich [418]

Answer:

2 3 5 7

Step-by-step explanation:

6 0

3 years ago

Try these calculations using the<br>graphing calculator:<br>31 x 42 -<br>443-637 -

puteri [66]

Answer:

31 × 42 = 1,302

443 – 637 = -194

Step-by-step explanation:

4 0

4 years ago

Melissa bought a sweater on sale for $24.95. This is $8.04 less than the price that Christine paid for the same sweater when is

Monica [59]

24.95 + 8.04 = 32.99

Christine paid $32.99

7 0

3 years ago

Is the following true or false? d/dx[x^3e^x]=x^2e^x (3x+2)

wolverine [178]

It's false. It's a product so...
Derivative of the first TIMES the second PLUS derivative of second TIMES the first.

Derivative of the first (x^3) = 3x^2
Times the second = 3x^2 * e^x

Derivative of the second = e^x (remains unchanged)
Times the first = e^x * x^3
So the answer would be (3x^2)(e^x) + (e^x)(x^3)
which can be factorised to form x^2·e^x(3 + x)

3 0

3 years ago