Answer:
You plot the points on the coordinates of [3, 0], [-1, 0], [-3, 0].
Step-by-step explanation:
You set the whole thing equal to zero, and when evaluated correctly, you come up with the above answer.
I am joyous to assist you anytime.
I am pretty sure you can only make one.
If two sides are known, and one of the angles, then the other bits can be deduced and are fixed.
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Answer:
a) C x +x +x +3x +3x = 18
b) x = 2
c) 2 cm, 6 cm
Step-by-step explanation:
a) The sum of the lengths of the sides is equal to the length of the perimeter. The appropriate equation is ...
x +x +x +3x +3x = 18
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b) Simplifying, the equation becomes ...
9x = 18
x = 2 . . . . . divide by 9
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c) The shorter sides are x = 2 cm.
The longer sides are 3x = 6 cm.
For this case we have the following function:
Where,
g: number of gallons of gas
M (g): number of miles that Danny's truck travels
We know that the maximum capacity is 20 gallons of gas.
Therefore, the maximum distance the truck can travel is given by:
Thus, the domain of the function is:

The range of the function is:
Answer:
A domain and range that are reasonable for the function are:
D. D: 0 ≤ g ≤ 20
R: 0 ≤ M (g) ≤ 340
Answer:
The probability is 0.0052
Step-by-step explanation:
Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:
P(A/B) = P(A∩B)/P(B)
The probability P(B) that at least three are aces is the sum of the following probabilities:
- The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
- There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

So, the number of ways to select exactly 3 aces is:

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725
Then, the probability P(B) that at least three are aces is:

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:
P(A∩B) = 1/270,725
Finally, the probability P(A/B) that all four are aces given that at least three are aces is:
