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3 years ago

PlZZZZZZZZZ HELP URGENTTTTTTTTTt

Mathematics

2 answers:

hjlf3 years ago

6 0

The solutions are 0 and 2

Aka the roots or x-intercepts of the parabola

ale4655 [162]3 years ago

3 0

The answer is 0 and 2 hope this helps

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Can someone please check my answers I WIILL GOVE BRAINLY TO FIRST PERSON THAT ANSWERS!

Rainbow [258]

The first is C. r = 4(4/9)
the second one is B. h = 130
the second one is A. k = 7

i’m so sorry, they’re all wrong

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3 years ago

The factorization of x^2 + 3x-4 is modeled with algebra tiles

o-na [289]

Answer:

(x-1) (x+4)

Step-by-step explanation:

i used something called the box method, basically the way i got the answer is what equals 3 when added, but multiplies to make -4

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3 years ago

Type the expressions as radicals. q ^ (3/2)

melisa1 [442]

Answer:

$\sqrt{q^3}$

Step-by-step explanation:

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3 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

How do I Draw the graph of the function f(x) = 3⌊x⌋ for the domain −1 ≤ x < 2

oksano4ka [1.4K]

Go to the website symbolab.com
or Mathpap.com and that should help give you your answer

8 0

3 years ago