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oksano4ka [1.4K]
3 years ago
7

What is the total amount of 2/5+5/3+9/3 and the lowest common denominator?

Mathematics
1 answer:
gregori [183]3 years ago
4 0

The lowest common denominator is lcm(5, 3), which is 15.

The sum of 2/5 + 5/3 + 9/3 is 6/15 + 25/15 + 45/15, which is 76/15 or 5\frac{1}{15}.

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Express the area of the entire rectangle.
Elza [17]

Answer:

Step-by-step explanation:

7 0
2 years ago
Write an algebraic expression for the verbal expression<br> the quotient for 45 and r
Nimfa-mama [501]

Answer:

45/r

Step-by-step explanation:

You're just doing 45 divided by r.

4 0
2 years ago
3. The area of a rectangular deck, in square meters, is given by the polynomial 40p2 + 24p.
lorasvet [3.4K]

Answer:

Length = 5p + 3

Perimeter = 26p + 6

Step-by-step explanation:

Given

Area = 40p² + 24p

Width = 8p

Solving for the length of deck

Given that the deck is rectangular in shape.

The area will be calculated as thus;

Area = Length * Width

Substitute 40p² + 24p and 8p for Area and Width respectively

The formula becomes

40p² + 24p = Length * 8p

Factorize both sides

p(40p + 24) = Length * 8 * p

Divide both sides by P

40p + 24 = Length * 8

Factorize both sides, again

8(5p + 3) = Length * 8

Multiply both sides by ⅛

⅛ * 8(5p + 3) = Length * 8 * ⅛

5p + 3 = Length

Length = 5p + 3

Solving for the perimeter of the deck

The perimeter of the deck is calculated as thus

Perimeter = 2(Length + Width)

Substitute 5p + 3 and 8p for Length and Width, respectively.

Perimeter = 2(5p + 3 + 8p)

Perimeter = 2(5p + 8p + 3)

Perimeter = 2(13p + 3)

Open bracket

Perimeter = 2 * 13p + 2 * 3

Perimeter = 26p + 6

4 0
3 years ago
Find the iqr of 4 5 6 8 9 10 11 12
77julia77 [94]

Answer:

The interquartile range is 5.

Step-by-step explanation:

Ah, a throwback to interquartile range... let me help :)

4,5,6,8,9,10,11,12

First, you need to know how to use the IQR. The interquartile range is basically known as the process of subtracting the upper quartile and the lower quartile of a set of data. The lower quartile should be written as Q1, and the upper quartile would be labeled as Q3. This would make the midpoint (median) data set Q2, and the highest possible point would be labeled Q4. Next, you have to always understand what you are looking at. For example, let's split the set 5,6,7,8,9,10,11,12 into groups. 5 and 6 would be Q1, 7 and 8 would be Q2, 9 and 10 would be Q3, and last but not least, 11 and 12 would be labeled as Q4. Now take Q1 and subtract it from Q3 and that is how you get your IQR.



3 0
3 years ago
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What is the surface area of the right rectangular prism?<br>center your answer in the box.
Firlakuza [10]
I believe the answer is 22 in^2
3 0
3 years ago
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