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Yanka [14]
3 years ago
12

choose the equation that shows a step in the process of completing the square on the given quadratic. y = x2 8x – 3 y = x2 8x 8

– 3 – 8 y = x2 8x 8 – 3 8 y = x2 8x 16 – 3 – 16 y = x2 8x 16 – 3 16
Mathematics
2 answers:
posledela3 years ago
3 0
Y = x^2 + 8x - 3
y = x^2 + 8x + (8/2)^2 - 3 - (8/2)^2
y = x^2 + 8x + 16 - 3 - 16
anastassius [24]3 years ago
3 0

Answer:

The next step will be : x^{2}+8x+16-3-16.

Step-by-step explanation:

we are given a quadratic equation as:

y=x^2+8x-3

now we have to find next step in the process for completing the square on the given quadratic

y=x^2+4^{2}+2\ \times x \times4-4^{2}-3

y=x^2+8x+16-3-16

Hence, the next step will be y=x^2+8x+16-3-16.


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alex41 [277]

Answer:

<em>10x + 50 =1 +5</em>

<em>10x=6-50</em>

<em>10x=-44</em>

<em>x=-4.4</em>

Step-by-step explanation:

4 0
3 years ago
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each paperclip is 7/8 of an inch long and costs $.03. exactly enough paper clips are laid end to end yo have a total length of 5
GalinKa [24]
1 clipe..............7/8
x.......................56

7x/8 = 56
7x = 56*8
x = 56*8/7
x = 8*8
x = 64 clipes

1 clipe = 0,03
64 clipes = 0,03*64
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5 0
3 years ago
Suppose that F(x) = x^3 and G(X) = -3x^3. Which statement best compares the
Alik [6]

Answer:

D. The graph of G(x) is the graph of F(x) flipped over the y-axis and

stretched vertically.

Step-by-step explanation:

since there is a negative, there must be a reflection. the reflection is over the y-axis because it is outside the x-value (-F(x) not F(-x))

the same goes for the vertical stretch. we know it is a vertical stretch because the 3 is outside the x-value (3F(x) not F(3x))

6 0
3 years ago
Please help me on this quick!! Thanks and please show work.
FinnZ [79.3K]
The two parallel bases b1 and b2 are
b1 = 12
b2 = 9
the order of which base you pick doesn't matter

The height is h = 10 and it's perpendicular to each base.

The area is...

A = (1/2)*h*(b1+b2)
A = (1/2)*10*(12+9)
A = (1/2)*10*(21)
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8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cpi%20%20x%5E%7B2%7D%20" id="TexFormula1" title=" \pi x^{2} " alt=" \pi x^{2} " align="
ANEK [815]

The formule is about area of a circle.

\pi x^{2} = a

We need to solve the equation for x. Where x is the radius of the circle.

In order to solve it for x, we need isolate it for x on left side.

So, first we need to get rid pi from left side.

On dividing both sides by pi, we get

\frac{\pi x^2}\pi}=\frac{a}{\pi}

x^2=\frac{a}{\pi}

Taking square root on both sides, we get

\sqrt{x^2}=\sqrt{\frac{a}{\pi}}

x=\sqrt{\frac{a}{\pi}}


4 0
3 years ago
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