Answer:
81.9%
Step-by-step explanation:
In a data set with a normal distribution the mean is 59 and standard deviation is three about what percent of the data live between 53 and 62
Using z score formula
z = (x-μ)/σ, where
x is the raw score,
μ is the population mean = 59
and σ is the population standard deviation = 3
For x = 53
z = 53 - 59/3
= -2
P-value from Z-Table:
P(x = 53) = 0.02275
For x = 62
z = 62 - 59/3
= 1
P-value from Z-Table:
P(x = 62) = 0.84134
Hence, the probability of the data live between 53 and 62 is
0.84134 - 0.02275
0.81859
Converting to Percentage.= 0.81859
× 100 = 81.859%
Approximately = 81.9%
Answer:
the answer is B
Step-by-step explanation:
x1.07 means an increase of 7%
so answer is 14 x 1.07, B
please mark as brainliest tyyyyy
Answer:
1/38 of Kelly's beads are blue.
Step-by-step explanation:
four eighths = 1/2 or 1 half
1/2 of them are red.
18 white beads, so number of red beads have to be bigger than 18 since she has blue beads too.
So, we can just estimate she has just one blue bead so then the 18 whites become 19 so we need to make red beads the same amount as it is half of the total.
The total is 38 since 19 + 19 = 38 (total beads)
So, blue is 1/38 as a fraction.
Hope this helps. :)
Answer:
Reduce the expression, if possible, by cancelling the common factors.[(2/3)^2]^3 X (2/3)^2 ÷ (2/3)^8 = 1
Step-by-step explanation:
4/9^3 x (2/3)^2 ÷ (2/3)^8
4/9^3 x 4/9 ÷ (2/3)^8
4/9^3 x 4/9 divided by 256/6561
64/729 x 4/9 divided by 256/6561
= 1
Answer:
4:18 pm
Step-by-step explanation:
An airport offers 2 shuttles that run on different schedules.If both shuttles leave the airport at 4:00 p.m.,at what time will they next leave theairport together.
Shuttle A leaves every 6 minutes
Shuttle B leaves every 9 minutes
Solution
To solve for when next both shuttles will leave the airport together, find the least common multiples of 6 minutes and 9 minutes
Shuttle A (every 6 minutes) = 6, 12, 18, 24
Shuttle B (every 9 minutes) = 9, 18, 27, 36
The least common multiples of 6 minutes and 9 minutes is 18 minutes
4:00 pm + 18 minutes
= 4:18 pm
The next time both shuttles will leave theairport together is 4:18 pm of the same day
