Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
Answer:
the total due including tip is 55.20
The correct statement is D.
Step-by-step explanation:
Given,
For backyard
Length = 5x-2
Width = 2x+4
For house
Length = 5x-2
Width = 4x-12
For driveway
Length = x+10
Width = 4x-12
To find the correct statement.
Formula
The area of a rectangle = Length × Width
So,
The area of the house and the driveway = (5x-2)(4x-12) + (x+10)(4x-12)
= (4x-12)(5x-2+x+10)
= (4x-12)(6x+8)
=
= 
So, the correct statement is D
You can cross check the other statements.
Answer:
Step-by-step explanation:
-9pi/8
23pi/8
-25pi/8
I think its.
Answer:
704
Step-by-step explanation:
7000 + 40 (7 thousands + 4 Tens) Divide that by 10.
7040/10 = 704
