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3 years ago

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which experimental probability from coach nelson's experiment equals the theorectical probability? what is this probability?

1 answer:

Lilit [14]3 years ago

7 0

Answer:

QUESTION:

which experimental probability from coach nelson's experiment equals the theorectical probability? what is this probability?

ANSWER:

This will explain everything to you.

https://www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-probability-statistics/cc-7th-theoretical-and-experimental-probability/v/comparing-theoretical-to-experimental-probabilites

Step-by-step explanation:

Hope that this helps you out! :)

If you have any questions please put them in the comment section below this answer.

Have a great rest of your day/night!

Please thank me on my profile if this answer has helped you.

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CAN SOMEONE HELP ME IN THIS INTEGRAL QUESTION PLS

finlep [7]

Due to the symmetry of the paraboloid about the <em>z</em>-axis, you can treat this is a surface of revolution. Consider the curve $y=x^2$ , with $1\le x\le2$ , and revolve it about the <em>y</em>-axis. The area of the resulting surface is then

$\displaystyle2\pi\int_1^2x\sqrt{1+(y')^2}\,\mathrm dx=2\pi\int_1^2x\sqrt{1+4x^2}\,\mathrm dx=\frac{(17^{3/2}-5^{3/2})\pi}6$

But perhaps you'd like the surface integral treatment. Parameterize the surface by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u^2\,\vec k$

with $1\le u\le2$ and $0\le v\le2\pi$ , where the third component follows from

$z=x^2+y^2=(u\cos v)^2+(u\sin v)^2=u^2$

Take the normal vector to the surface to be

$\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial u}=-2u^2\cos v\,\vec\imath-2u^2\sin v\,\vec\jmath+u\,\vec k$

The precise order of the partial derivatives doesn't matter, because we're ultimately interested in the magnitude of the cross product:

$\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|=u\sqrt{1+4u^2}$

Then the area of the surface is

$\displaystyle\int_0^{2\pi}\int_1^2\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\int_0^{2\pi}\int_1^2u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv$

which reduces to the integral used in the surface-of-revolution setup.

7 0

3 years ago

I need to look for an answer for 3,547x523 please I need to know the answer please I would be really happy if you give me an ans

photoshop1234 [79]

You can use a calculator for this:

3547*523 = 1332081

3 0

3 years ago

Answer the circled ones and ill give brainiest!!

sergejj [24]

8B and 10 not sure probably centre??

3 0

3 years ago

Janice thinks that 20 hundredths is equivalent to 2 thousandths because 20 hundreds is equal to 2 thousands. Use words and a pla

expeople1 [14]

<em><u>Explanation</u></em>:

On the left hand side of the place value chart, 20 hundreds is equal to 2 thousands because thousands is larger than hundreds. 2 thousands is 2(1000)=2000. 20 hundreds is 20(100)=2000. They are the same number.

However, on the right hand side of the place value chart, hundredths is larger than thousandths. To say that 20 hundredths is the same as 2 thousandths is incorrect, because you're saying more of a larger quantity is the same as less of a smaller quantity.

Hundredths are two places after the decimal, and have a value of 0.01. 20 hundredths is 20(0.01) = 0.2.

Thousandths are three places after the decimal and have a value of 0.001. 2 thousandths is 2(0.001) = 0.002.

We can write 0.2 as 0.200; this way we can see that 0.200 is larger than 0.002. They are not equal.

3 0

4 years ago

Read 2 more answers

Solve the system of equations by substitution 3x+y=9z

poizon [28]

Answer:

x = 1.27

y = 5.18

Step-by-step explanation:

to solve this system of equation by simultaneous equation we say that let

3x+y=9.............................. equation 1

-5x+2y=4 .......................... equation 2

from equation 1

3x+y=9.............................. equation 1

y = 9 -3x.............................. equation 3

substitute the value of y = 9 -3x into equation 2

-5x+2y=4 .......................... equation 2

-5x + 2( 9 -3x) = 4

-5x + 18 - 6x = 4

collect the like terms

18 - 4 = 6x + 5x

14 = 11x

divide both side by 11

14/11 = 11x/11

x = 14/11

x = 1.27

put the value of x = 1.27 into equation 3

y = 9 -3x.............................. equation 3

y = 9 - 3( 1.27)

y = 9 - 3.82

y = 5.18

<em>to check if you are correct put the value of x and y into either equation 1 or equation 2.</em>

<em>3x+y=9.............................. equation 1</em>

<em>3( 1.27) + 5.18 = 9</em>

<em>3.81 + 5.18 = 9</em>

<em>9 = 9</em>

3 0

3 years ago