Question

PLEASE CAN ANYONE HELP ME? I'M SO STUCK. I WILL GIVE BRAINLIEST! 5 STARS AND A THANKS!

Answer 1

Answer:

Option A.

Step-by-step explanation:

The given piecewise function is

$f(x)=\begin{cases}-\left(x+1\right)^{2}+2 & \text{ if } x$

From the given function it is clear that function is divided at x=-1 and x=2. It means we check the discontinuity at x=-1 and x=2.

For x=-1,

$f(-1)=-(-1)+2=3$

LHL: $lim_{x\rightarrow -1^-}f(-1)=-\left(-1+1\right)^{2}+2=2$

Since LHL ≠ f(-1), therefore the given function is discontinuous at x=-1.

For x=2,

$f(2)=\sqrt{2-1\ }=1$

LHL: $lim_{x\rightarrow 2^-}f(2)=-(2)+2=0$

Since LHL ≠ f(2), therefore the given function is discontinuous at x=2.

Therefore, the correct option is A.

Answer 2

Answer:

x = -1 and 2

Step-by-step explanation:

i dont really know how to explain it but i have endmentum which is considered plato and the answer IS X = -1 and 2 i promise i just took it and it was correct!!