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2 years ago

Help guys I need this

Mathematics

1 answer:

velikii [3]2 years ago

4 0

Answer:

768 Square Inches

Step-by-step explanation:

10x18 = 180 (2 rectanlge faces)

12x8 = 96 (2 triangles)

12x18 = 216 (bottom face)

216 + 96(2) + 180(2) =

768

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Twelve and thirty- eight hundredths.

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3 years ago

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Could you please help me? -0.7-(-2.5)=

Reika [66]

-0.7 - (-2.5) =

-0.7 + 2.5 =

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3 years ago

Wright an Expression to represent: three minus the product of two and a number z

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Answer:

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Step-by-step explanation:

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3 years ago

Draw a line segment 7cm long .

White raven [17]

Answer:

The line segment 7 cm long is shown below.

Step-by-step explanation:

First we draw a line line segment whose length is 7 cm long. Then we divide the line in small parts.

The length of each part is 1 cm.

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From the figure it is noticed that we have total 7 small parts and length of each part is 1 cm. So length of 7 parts is

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4 0

3 years ago

Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).

insens350 [35]

Answer:

$\cos{\theta} = \dfrac{1}{52}$

$\csc{\theta} = \dfrac{52}{\sqrt{2703}}$

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

$\sec{\theta} = \dfrac{1}{\cos{\theta}}$

we can substitute the value of sec(θ) in this equation:

$52 = \dfrac{1}{\cos{\theta}}$

and solve for for cos(θ)

$\cos{\theta} = \dfrac{1}{52}$

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by $\theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ$

b) since right triangle is mentioned in the question. We can use:

$\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}$

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

length of the adjacent side = 1
length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

$(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2$

$(52)^2=(1)^2+(\text{opp})^2$

$\text{opp}=\sqrt{(52)^2-1}$

$\text{opp}=\sqrt{2703}$

length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

$\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}$

$\sin{\theta} = \dfrac{\sqrt{2703}}{52}}$

and since $\csc{\theta} = \dfrac{1}{\sin{\theta}}$

$\csc{\theta} = \dfrac{52}{\sqrt{2703}}$

4 0

3 years ago