Since g(6)=6, and both functions are continuous, we have:
![\lim_{x \to 6} [3f(x)+f(x)g(x)] = 45\\\\\lim_{x \to 6} [3f(x)+6f(x)] = 45\\\\lim_{x \to 6} [9f(x)] = 45\\\\9\cdot lim_{x \to 6} f(x) = 45\\\\lim_{x \to 6} f(x)=5](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2Bf%28x%29g%28x%29%5D%20%3D%2045%5C%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2B6f%28x%29%5D%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B9f%28x%29%5D%20%3D%2045%5C%5C%5C%5C9%5Ccdot%20lim_%7Bx%20%5Cto%206%7D%20f%28x%29%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20f%28x%29%3D5)
if a function is continuous at a point c, then
,
that is, in a c ∈ a continuous interval, f(c) and the limit of f as x approaches c are the same.
Thus, since
, f(6) = 5
Answer: 5
Answer:
You can plot the lines by putting the values of x and y.
For y=x-2, if we put x= 2, then we got y=0
So, the point for this equation will be (2,0). Similarly, you can get many points for the equations and join them to plot lines in the graph.
Answer:
y=7x-75
Step-by-step explanation:
use poiint slope formula
Graphing an inequality on a number line, is very similar to graphing a number. For instance, look at the top number line x = 3. We just put a little dot where the '3' is, right?
Now an inequality uses a greater than, less than symbol, and all that we have to do to graph an inequality is find the the number, '3' in this case and color in everything above or below it.
Just remember
if the symbol is (≥ or ≤) then you fill in the dot, like the top two examples in the graph below
if the symbol is (> or <) then you do not fill in the dot like the bottom two examples in the graph below
