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3 years ago

Is it possible to solve the differential equation

Mathematics

1 answer:

deff fn [24]3 years ago

6 0

Answer:

No, and solutions is is not valid.

Step-by-step explanation:

Solving y'(x)= y(x)a|x| by parts yields y(x)= $e^{\frac{a}{2}x^{2} }$ is the solutions, for y(0)=0 (initial value), it yields $e^{0}=0$ which is not valid. Note a is assumed to be constant.

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Please help how do I do this

Mkey [24]

Answer:

for the tables, replace x for the numbers in the x column. for example, when x = 0, you’ll do y = 0.60(0) + 40

y = 0 + 40

y = 40

and do that for the rest of them

Step-by-step explanation:

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4 years ago

Write each fraction in simplest form<br> 6/24

Marta_Voda [28]

Answer:1/4

Step-by-step explanation:

Hope this helped

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3 years ago

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Find the equation of the line passing through the points (-2/3,1) and (-2,1/2). Write the equation in standard form.

7nadin3 [17]

Standard form is y = mx + b.
To find the slope, m, we must find the 'rise over run,' or the difference in y divided by the difference in x. We do this by:
$\frac{y1 - y2}{x1 - x2} = \frac{ (- \frac{2}{3} ) - ( -2 )}{(1) - ( \frac{1}{2} ) } = \frac{ \frac{4}{3} }{ \frac{1}{2} } \\ = \frac{4}{3} \times \frac{2}{1} = \frac{8}{3}$
Therefore, the slope is 8/3.

To find b, we must plug in the slope and one point:
$(1) = ( \frac{8}{3} )( - \frac{2}{3} ) + b \\ 1 = - \frac{16}{9} + b \\ \frac{25}{9} = b$
Therefore, b is 25/9, and the total equation is
$y = \frac{8}{3} x + \frac{25}{9}$

3 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

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3 years ago

Which expression would you use to find the number of outcomes for flipping 4 coins?

Papessa [141]

The answer would be 2(4)

3 0

3 years ago

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