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Nat2105 [25]
3 years ago
11

Can someone pls help me -n-

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0

Answer:

(2, -7)

Step-by-step explanation:

thanks for your time sorry if i got it wrong.

Have a great day.

(>.<) <3 Kris

olga55 [171]3 years ago
4 0
I like math-way it will help you a lot
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A cone with volume 246 ft cubic if the height is 15 find the radius
Liula [17]

Answer:

r = 3.95 ft

Step-by-step explanation:

Volume of cone = \frac{1}{3} \pi r^{2} h = 246 ft³

246 = \frac{1}{3} * \frac{22}{7} * r^2 * 15

r² = \frac{246*3*7}{22*15*5}

r = \sqrt{15.65}

r = 3.95 ft

8 0
3 years ago
You are designing a miniature golf course and need to calculate the surface area and volume of many of the objects that will be
laiz [17]
a. To solve the first part, we are going to use the formula for the surface area of a sphere: A=4 \pi r^2
where
A is the surface area of the sphere
r is the radius of the sphere
We know from our problem that r=5ft; so lets replace that value in our formula:
A=4 \pi (5ft)^2
A=314.16ft^2

To solve the second part, we are going to use the formula for the volume of a sphere: V= \frac{4}{3}  \pi r^3
Where
V is the volume of the sphere
r is the radius 
We know form our problem that r=5ft, so lets replace that in our formula:
V= \frac{4}{3}  \pi (5ft)^3
V=523.6ft^3

We can conclude that the surface area of the sphere is 314.16 square feet and its volume is 523.6 cubic feet.

b. To solve the first part, we are going to use the formula for the surface area of a square pyramid: A=a^2+2a \sqrt{ \frac{a^2}{4} +h^2}
where
A is the surface area
a is the measure of the base
h is the height of the pyramid 
We know form our problem that a=8ft and h=12ft, so lets replace those value sin our formula:
A=(8ft)^2+2(8ft) \sqrt{ \frac{(8ft)^2}{4} +(12ft)^2}
A=266.39ft^2

To solve the second part, we are going to use the formula for the volume of a square pyramid: V=a^2 \frac{h}{3}
where
V is the volume 
a is the measure of the base
h is the height of the pyramid
We know form our problem that a=8ft and h=12ft, so lets replace those value sin our formula:
V=(8ft)^2 \frac{(12ft)}{3}
V=256ft^3

We can conclude that the surface area of our pyramid is 266.39 square feet and its volume is 256 cubic feet.

c. To solve the first part, we are going to use the formula for the surface area of a circular cone: A= \pi r(r+ \sqrt{h^2+r^2}
where
A is the surface area
r is the radius of the circular base
h is the height of the cone
We know form our problem that r=5ft and h=8ft, so lets replace those values in our formula:
A= \pi (5ft)[(5ft)+ \sqrt{(8ft)^2+(5ft)^2}]
A=226.73ft^2

To solve the second part, we are going to use the formula for the volume os a circular cone: V= \pi r^2 \frac{h}{3}
where
V is the volume
r is the radius of the circular base
h is the height of the cone 
We know form our problem that r=5ft and h=8ft, so lets replace those values in our formula:
V= \pi (5ft)^2 \frac{(8ft)}{3}
V=209.44ft^3

We can conclude that the surface area of our cone is 226.73 square feet and its surface area is 209.44 cubic feet.

d. To solve the first part, we are going to use the formula for the surface area of a rectangular prism: A=2(wl+hl+hw)
where
A is the surface area
w is the width
l is the length 
h is the height
We know from our problem that w=6ft, l=10ft, and h=16ft, so lets replace those values in our formula:
A=2[(6ft)(10ft)+(16ft)(10ft)+(16ft)(6ft)]
A=632ft^2

To solve the second part, we are going to use the formula for the volume of a rectangular prism: V=whl
where
V is the volume 
w is the width
l is the length 
h is the height
We know from our problem that w=6ft, l=10ft, and h=16ft, so lets replace those values in our formula:
V=(6ft)(16ft)(10ft)
V=960ft^3

We can conclude that the surface area of our solid is 632 square feet and its volume is 960 cubic feet.

e.  Remember that a face of a polygon is a side of polygon.
    - A sphere has no faces.
    - A square pyramid has 5 faces.
    - A cone has 1 face.
    - A rectangular prism has 6 faces.
Total faces: 5 + 1 + 6 = 12 faces

<span>We can conclude that there are 12 faces in on the four geometric shapes on the holes.
</span>
f. Remember that an edge is a line segment on the boundary of the polygon.
   - A sphere has no edges.
   - A cone has no edges.
   - A rectangular pyramid has 8 edges.
   - A rectangular prism has 12 edges.
Total edges: 8 + 20 = 20 edges

Since we have 20 edges in total, we can conclude that your boss will need 20 brackets on the four shapes.

g. Remember that the vertices are the corner points of a polygon.
   - A sphere has no vertices.
   - A cone has no vertices.
   - A rectangular pyramid has 5 vertices.
   - A rectangular prism has 8 vertices.
Total vertices: 5 + 8 = 13 vertices

We can conclude that there are 0 vertices for the sphere and the cone; there are 5 vertices for the pyramid, and there are are 8 vertices for the solid (rectangular prism). We can also conclude that your boss will need 13 brackets for the vertices of the four figures.

7 0
3 years ago
0.25x-8=16 what value of x makes the equation true?
prohojiy [21]
0.25x-8=16 add 8 to both sides. you get 0.25x=8. divide by .25 on each side x=32
8 0
4 years ago
Please help me with my homework!!! Number 4
grigory [225]
Ill say about $
1125 over 5 years
7 0
3 years ago
Alan bowls one game, which consists of 10 frames. The number of pins he knocked down in each frame is 5, 6, 7, 5, 7, 9, 2, 4, 8,
mote1985 [20]
Alan shoud use mean and range, mean is where you add all of the numbers up and divide by how many numbers there are, and range where you take the highest number and subtract it by the lowest number. This way he will find the greatest and least number of pins he knocked down 
7 0
3 years ago
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