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tino4ka555 [31]
3 years ago
14

Answer please ! both questions 7 and 8

Mathematics
1 answer:
Elodia [21]3 years ago
3 0

Answer:

7) p=80

8)z= 19.2

Step-by-step explanation:

7th problem)

0.1p=8

p * 10^{-1}=8

\frac{p}{10}=8

p=80

8th problem)

\frac{z}{2.4}=8

z=8*2.4

z=19.2

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Graph △XYZ with vertices X(2, 3), Y(−3, 2), and Z(−4,−3) and its image after the translation (x, y)→(x+3, y−1)
viktelen [127]

Answer:

  • X'(5, 2)
  • Y'(0, 1)
  • Z'(-1, -4)

Step-by-step explanation:

The translation increases each x-coordinate by 3, moving the point 3 units to the right. It decreases each y-coordinate by 1, moving the point 1 unit down.

  (x, y) ⇒ (x+3, y-1)

  X(2, 3) ⇒ X'(5, 2)

  Y(-3, 2) ⇒ Y'(0, 1)

  Z(-4, -3) ⇒ Z'(-1, -4)

The red arrows show the translation of each point in the graph.

5 0
4 years ago
What is the value of each expression (-3)2
k0ka [10]

First you had to remove parenthesis first.

-3*2=-6

Multiply by the numbers.

3*2=6

Final answer \boxed{=-6}

6/3=2

2*3=6

6/2=3

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

5 0
3 years ago
In a seminar of 1200 people, 65 percent were women, How many men were in the seminar?
Nookie1986 [14]

Answer:

420

Step-by-step explanation:

If there were 1200 people, and 65 percent were women, that means the rest of the crowd are men, which is 35 percent. By multiplying 35 percent by the overall population, 1200, (1200*35/100), you'll get 420 men.

4 0
3 years ago
Read 2 more answers
Please help me this question​
ANTONII [103]

Answer:

0

Step-by-step explanation:

bcoz 2^5 X 9²=2592

so the difference is 0

5 0
3 years ago
Read 2 more answers
How many positive integers $n$ from 1 to 5000 satisfy the congruence $n \equiv 5 \pmod{12}$?
irga5000 [103]
The equivalence n \equiv 5 \pmod{12}

means that n-5 is a multiple of 12.

that is

n-5=12k, for some integer k

and so

n=12k+5


for k=-1, n=-12+5=-7

for k= 0, n=0+5=5 (the first positive integer n, is for k=0)


we solve 5000=12k+5 to find the last k

12k=5000-5=4995

k=4995/12=416.25

so check k = 415, 416, 417 to be sure we have the right k:

n=12k+5=12*415+5=4985

n=12k+5=12*416+5=4997

n=12k+5=12*417+5=5009


The last k which produces n<5000 is 416


For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,

thus there are 417 integers n satisfying the congruence.


Answer: 417

6 0
4 years ago
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