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tino4ka555 [31]
3 years ago
14

Answer please ! both questions 7 and 8

Mathematics
1 answer:
Elodia [21]3 years ago
3 0

Answer:

7) p=80

8)z= 19.2

Step-by-step explanation:

7th problem)

0.1p=8

p * 10^{-1}=8

\frac{p}{10}=8

p=80

8th problem)

\frac{z}{2.4}=8

z=8*2.4

z=19.2

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Jarry is making a strawberry smoothie which measure is greatest the amount of milk cottage cheese or strawberry
Stells [14]

Answer:

Milk

Step-by-step explanation:

The amount of milk, cottage cheese and strawberries used are given in the attached picture.

3/4 cup of milk

2/6 cup cottage cheese

8/12 cup strawberry

Converting the fractions to decimal :

3/4 cup of milk = 0.75

2/6 cup cottage cheese = 0.3333

8/12 cup strawberry = 0.66666

0.75 > 0.6666 > 0.3333

We can conclude that amount of milk is greatest, then strawberry and the least is cottage cheese.

8 0
3 years ago
What is the approximate area of a circle shown below?
hoa [83]

To find the area of a circle, the equation we use is 3.14*r^2.

We know 17^2 is 289.

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6 0
2 years ago
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You return from a trip with 480 Canadian dollars. How much are your Canadian dollars worth in U.S. dollars? Use the exchange rat
Sever21 [200]

591 Dollars 42 Cents (591 Dollars when rounded)

6 0
3 years ago
What is the vertex of this parabola? y= 2x² + 4x +5
uranmaximum [27]

Answer:

vertex = (- 1, 3 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = 2x² + 4x + 5 ← is in standard form

with a = 2, b = 4, then

x_{vertex} = - \frac{4}{4} = - 1

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3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
2 years ago
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