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2 years ago

Find the surface area and the volume of the figure Round to the nearest tenth if needed.

Mathematics

2 answers:

musickatia [10]2 years ago

6 0

Answer:

> V = 217.68 cm³

> S = 227.14 cm²

Step-by-step explanation:

We are required to find the surface area and the volume of the given figure . This question is from Combination of solids . As we can see that this figure is made up of a cuboid and cylinder.

Firstly let's find out the volume .

> V = V_( cuboid) + V_(cylinder)

> V = 9cm × 4cm × 5cm + π × ( 2cm)²× 3cm

> V = 180 cm³ + 3.14 × 4cm² × 3cm

> V = 180 cm³ + 37.68 cm³

> V = 217.68 cm³

Lets find the surface area :-

> S = S_( cuboid) + S_( cylinder) - πr²

> S = 2( 9×4 + 4× 5 + 5×9) cm² + 2×π×2cm × 3cm - 3.14 × (2cm)²

> S = 239.7 cm² - 12.56 cm²

> S = 227.14 cm²

Note :-

Here we subtracted πr² from the total surface area of cuboid and cylinder because that much area of the cuboid was covered by the base of the cylinder .

elixir [45]2 years ago

4 0

Answer:

See below

Step-by-step explanation:

Surface area:

S = 2(lw + lh + wh) + 2πrh
S = 2(9*4 + 9*5 + 4*5) + 2*3.14*2*3 = 239.7 cm² (rounded)

Volume:

V = lwh + πr²h
V = 9*4*5 + 3.14*2²*3 = 217.7 cm³ (rounded)

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3 years ago

Read 2 more answers

Write each number 1. 1,000 more than 3,872

Mrac [35]

The value for a number that is 1000 more than 3,872 will be 4,872

In the given question, it is stated that we have to find out the value of the expression given. The expression states that we have to find out a number that is 1000 more than 3872.

This can easily be done. To find out the value for a number that is 1000 greater than 3872, we just need to add the value to the number i.e. we need to add 1000 to 3872. Let the new number be 'x'.

So, by solving this condition, we get

=> x = 3872 + 1000

=> x = 4872

Here we get x = 4872.

Hence, 1000 more than 3,872 will be 4,872.

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1 year ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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2 years ago

The lifetime of a certain type of TV tube has a normal distribution with a mean of 61 and a standard deviation of 6 months. What

Ad libitum [116K]

Answer:

$P(57$

$P(-0.67$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the lifetime for a TV of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,6)$