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lina2011 [118]
3 years ago
6

What can you use on the Internet to look for information?

Computers and Technology
1 answer:
4vir4ik [10]3 years ago
6 0

Answer:

I use Wikipedia to know anything

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Frequent cleaning with an air duster can would do the job
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Problem 1: you must write a method for this problem called sentenceAnalyzer Write a program that reads a sentence from the keybo
forsale [732]

Answer:

   static void sentenceAnalyzer(String sentence){

       int lenOfString = sentence.length()-1;

   

           if(sentence.charAt(lenOfString)=='.'){

               System.out.println("Declarative");

             

           }

           else   if(sentence.charAt(lenOfString)=='?'){

               System.out.println("Interrogative");

             

           }

           else if(sentence.charAt(lenOfString)=='!'){

               System.out.println("Exclamation");

             

           }

           else{

               System.out.println("Unknown");

             

           }

   

   }

Explanation:

Using Java programming language

Create the method as required

Obtain the index of the last element using the string length method

Use if and else statements to check if the character at the last index is equal to any of the characters given and print the expected output

see a complete code with the main method below

<em>import java.util.Scanner;</em>

<em>public class num11 {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        //Receiving User input</em>

<em>        System.out.println("Enter a sentence");</em>

<em>        String sentence = in.nextLine();</em>

<em>        // Calling the method</em>

<em>        sentenceAnalyzer(sentence);</em>

<em>    }</em>

<em>    static void sentenceAnalyzer(String sentence){</em>

<em>        int lenOfString = sentence.length()-1;</em>

<em />

<em>            if(sentence.charAt(lenOfString)=='.'){</em>

<em>                System.out.println("Declarative");</em>

<em>            }</em>

<em>            else   if(sentence.charAt(lenOfString)=='?'){</em>

<em>                System.out.println("Interrogative");</em>

<em>            }</em>

<em>            else if(sentence.charAt(lenOfString)=='!'){</em>

<em>                System.out.println("Exclamation");</em>

<em>            }</em>

<em>            else{</em>

<em>                System.out.println("Unknown");</em>

<em>            }</em>

<em>    }</em>

<em>}</em>

<em />

8 0
3 years ago
, how do you make this user <br> XtraCrispyIzzy<br> 12 characters or less for microsoft?
xxTIMURxx [149]

Answer:

Maybe take away the 'xtra'

8 0
3 years ago
A newspaper wants to estimate the proportion of Americans who will vote for Candidate A. A random sample of 1000 voters is selec
Finger [1]

Answer:

The correct answer to the following question will be "NORM.S.INV".

Explanation:

  • The NORM.IN.V function in Excel determines the opposite of the Cumulative Standard Distribution Function for just a value of x which is given, and the standard deviation and mean of the distribution provided. The probability of NORMINV(mean, probability, standard deviation).
  • In Excel 2010, the standard. S. Inv function is new and is therefore not easily accessible in Excel's earlier versions.

Therefore, NORM.S.INV is the right answer.

5 0
3 years ago
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