If the distance covered by an object in time t is given by s(t)=2t^2+3t , where s(t) is in meters and t is in seconds, what is t
he average velocity over the interval from 2 seconds to 4 seconds?
Answers:
a) 15m/s
b) 14m/s
c) 13m/s
d) 12m/s
e) 11m/s
1 answer:
Answer:
a) 15 m/s.
Step-by-step explanation:
s(t) = 2t^2+ 3t
Distance at 2 seconds = s(2) = 2(2)^2 + 3(2) = 14 m.
Distance at 4 seconds = s(4) = 2(4)^2 + 3(4) = 44 m.
Average velocity = distance travelled from t = 2 until t = 4 / time
= (44 - 14) / 4 -2
= 30/2
= 15 m / s.
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