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trapecia [35]
3 years ago
14

If the distance covered by an object in time t is given by s(t)=2t^2+3t , where s(t) is in meters and t is in seconds, what is t

he average velocity over the interval from 2 seconds to 4 seconds?
Answers:
a) 15m/s
b) 14m/s
c) 13m/s
d) 12m/s
e) 11m/s
Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

a) 15 m/s.

Step-by-step explanation:

s(t) = 2t^2+ 3t

Distance at 2 seconds =  s(2) = 2(2)^2 + 3(2) =  14 m.

Distance at 4 seconds =  s(4) = 2(4)^2 + 3(4) =  44 m.

Average velocity = distance travelled from t = 2 until t = 4 /  time

= (44 - 14) / 4 -2

= 30/2

= 15 m / s.

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Mr.Clark shared a quantity of mangoes among his 3 sons,Drake,Rafael and John in a ratio of 3:2:4 respectively. Drake received 63
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Drake: 63 Mangoes

Rafael: 42 Mangoes

John: 84 Mangoes

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3 years ago
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What is the probability of first drawing a red card, then a face card, and then a black card? Do not round your intermediate com
lozanna [386]

Answer:

 [ 26 / 425 ] ≈ 0.0612

Step-by-step explanation:

Solution:-

- First we will describe the standard deck of 52 cards in terms of black, red and face cards found in a standard deck

- Following is a table of distribution of colored and face card found in a standard deck:

                 Type                   Number of cards

                 1 - 10                                40

                 Black                               26

                 Red                                 26

                 Face                                12

- The numerical cards from digit ( 1 to 10 ) are found in all 4 suits ( Clubs, Diamonds, Spades, and Hearts ). Hence, 10 x 4 = 40

- The entire deck is split in two colors ( Red and Black ) equally. So, the number of Black and Red cards are = 52 / 2 = 26 cards.

- The face cards are of three types ( King, Queen and Jack ). These three face cards are found in each of the 4 suits. Hence, Total number of face cards are = 4 * 3 = 12

- We will now consider the probabilities asscociated with each type. We will define 3 events and write down their proability as expressed:

Event ( A ): First draw is a red card.

- The probability of this event can be determined with the help of the table given above. There are a total of 26 red card in a standard deck of 52 cards. Hence,

            p ( A ) = [ Number of red cards ] / [ Total cards in a deck ]

            p ( A ) = [ 26 ] / [ 52 ]

            p ( A ) = 1 / 2

- After we make the first draw of a red card. Our deck distribution is changed to Number of Red cards remaining = 25 and total deck now has 51 cards remaining.

- We will define the next event as:

Event ( B ): The second draw is a face card.

- The probability of this event can be determined with the help of the table given above. There are a total of 12 face cards in a standard deck of 52 cards which is now down to 51 cards. Hence,

            p ( B ) = [ Number of face cards ] / [ Total cards in a deck ]

            p ( B ) = [ 12 ] / [ 51 ]

            p ( B ) = 4 / 17

- After we make the first draw of a face card. Our deck distribution is changed to Number of Face cards remaining = 11 and total deck now has 50 cards remaining.

- We will define the next event as:

Event ( C ): The third draw is a black card.

- The probability of this event can be determined with the help of the table given above. There are a total of 26 black cards in the deck. The total number of cards are down to 50 cards only. Therefore,

            p ( C ) = [ Number of black cards ] / [ Total cards in a deck ]

            p ( C ) = [ 26 ] / [ 50 ]

            p ( C ) = 13 / 25

- The entire drawing process consists of 3 events which are dependent on each draw. However, for the overall event to occur i.e drawing a red card , then a face card, and then a black card. We will multiply all three outcomes as follows:

          p ( T ) = p ( A ) * p ( B ) * p ( C )

          p ( T ) = [ 1 / 2 ] * [ 4 / 17 ] * [ 13 / 25 ]

          p ( T ) =  [ 26 / 425 ] ≈ 0.0612

4 0
3 years ago
The system of equations shown below is graphed on a coordinate grid:
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3y+x=4

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x+3y-3y=4-3y

x=-3y+4

Substitute -3y+4 for x in -x+2y=6

-x+2y=6

-(-3y+4)+2y=6

Simplify both sides of the equation

5y-4=6

Add 4 to both sides

5y-4+4=6+4

5y=10

Divide both sides by 5

5y/5=10/5

y=2

Substitute 2 for y in x=-3y+4

x=-3y+4

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The answer is A

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Answer:

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Step-by-step explanation:

Given that the bag contains black and red marbles.

Number of black marbles in the bag = 2

Number of red marbles in the bag = 3

Total number of marbles in the bag = Number of black marbles + Number of red marbles = 2 + 3 = 5

Let us have a look at the formula for probability of an event E, which can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(\text{First red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5 }

Now, the marble chosen at first is replaced.

Therefore, the count remains the same.

P(\text{Second red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5}

Now, the <em>required probability</em> can be found as:

P(\text{First red marble})\times P(\text{Second red marble}) = \dfrac{3}{5}\times \dfrac{3}{5} = \bold{\dfrac{9}{25} }

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Answer:

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