Answer:
0.288 < p < 0.338
Step-by-step explanation:
We have 2331 adults polled and 730 said they believe in UFOs. We are to construct a 99% confidence interval for the population proportion. We are told to round to 3 decimal places as needed.
We need to find p-hat and q-hat
p-hat = 730/2331 = 0.313
q-hat = 1 - p-hat = 1 - 0.313 = 0.687
Since the sample size is greater than 30, we use a z-value for 99% confidence, which is 2.575
See attached photo for the construction of the confidence interval
Answer:
a) 3.5
b) 3.33
c) 
Step-by-step explanation:
As given,
A fair die is rolled 10 times
a)
Expected value of Sum of the number in 10 rolls = 
= 3.5
∴ we get
Expected value of Sum of the number in 10 rolls = 3.5
b)
Ley Y : number of multiples of 3
Y be Binomial
Y - B(n = 10, p =
)
Now,
Expected value = E(Y) = np = 10×
= 3.33
c)
Let m = total number of faces in a die
⇒m = 6
As die is roll 10 times
⇒n = 10
Now,
Let Y = number of different faces appears
Now,
Expected value, E(Y) = m - m
= 
Answer:
(c) 714.96 = 21.6(w +4.7)
Step-by-step explanation:
The area of the rectangular park will be the product of its length and width. This relation is used to write an equation to find the original width of the park.
<h3>Width</h3>
Let w represent the original width of the park in meters. The new width is 4.7 meters more, so is represented by (w +4.7).
<h3>Other dimensions</h3>
The length of the park is given as 21.6 meters. The area is given as 714.96 square meters.
<h3>Area formula</h3>
The various dimensions of the park are related by the area formula:
A = LW
714.96 = 21.6(w +4.7)
The length of a rectangle is 4 cm less than twice the width. express as an integer the maximum width of the rectangle when the perimeter is less than 78 cm.