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borishaifa [10]
3 years ago
7

What equivalent to 6/1

Mathematics
1 answer:
Vikki [24]3 years ago
7 0
That’s the simplest form of 6/1 but some equivalent fractions would be, 12/2 = 18/3 = 24/4 and more
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Mr. hewitt is hoping that Mrs. Hoffman will buy him a geometrically interesting piece of land on which he will build a castle. M
xxMikexx [17]
Did u figure it out?
6 0
3 years ago
In a survey of 23312331 ​adults, 730730 say they believe in UFOs. Construct a 99 %99% confidence interval for the population pro
serg [7]

Answer:

0.288 < p < 0.338

Step-by-step explanation:

We have 2331 adults polled and 730 said they believe in UFOs.  We are to construct a 99% confidence interval for the population proportion.  We are told to round to 3 decimal places as needed.  

We need to find p-hat and q-hat

p-hat = 730/2331 = 0.313

q-hat = 1 - p-hat = 1 - 0.313 = 0.687

Since the sample size is greater than 30, we use a z-value for 99% confidence, which is 2.575

See attached photo for the construction of the confidence interval

8 0
3 years ago
A fair die is rolled 10 times. Find the expected value of:a) the sum of the numbers in the ten rolls;b) the number of multiples
velikii [3]

Answer:

a) 3.5

b) 3.33

c) 6 - 6\left(\begin{array}{ccc}5\\6\end{array}\right)^{10}

Step-by-step explanation:

As given,

A fair die is rolled 10 times

a)

Expected value of Sum of the number in 10 rolls = \frac{1}{6}(1+2+3+4+5+6) = \frac{21}{6}

                                                                                = 3.5

∴ we get

Expected value of Sum of the number in 10 rolls = 3.5

b)

Ley Y : number of multiples of 3

Y be Binomial

Y - B(n = 10, p = \frac{2}{6} )

Now,

Expected value = E(Y) = np = 10×\frac{2}{6}  = 3.33

c)

Let m = total number of faces in a die

⇒m = 6

As die is roll 10 times

⇒n = 10

Now,

Let Y = number of different faces appears

Now,

Expected value, E(Y) = m - m\left(\begin{array}{ccc}m-1\\m\end{array}\right)^{n}

                                  = 6 - 6\left(\begin{array}{ccc}6-1\\6\end{array}\right)^{10} = 6 - 6\left(\begin{array}{ccc}5\\6\end{array}\right)^{10}

5 0
3 years ago
City planners are planning to build a new community park. They agree that the park will be rectangular in shape, but the propose
podryga [215]

Answer:

  (c)  714.96 = 21.6(w +4.7)

Step-by-step explanation:

The area of the rectangular park will be the product of its length and width. This relation is used to write an equation to find the original width of the park.

<h3>Width</h3>

Let w represent the original width of the park in meters. The new width is 4.7 meters more, so is represented by (w +4.7).

<h3>Other dimensions</h3>

The length of the park is given as 21.6 meters. The area is given as 714.96 square meters.

<h3>Area formula</h3>

The various dimensions of the park are related by the area formula:

  A = LW

  714.96 = 21.6(w +4.7)

4 0
2 years ago
Help please
geniusboy [140]
The length of a rectangle is 4 cm less than twice the width. express as an integer the maximum width of the rectangle when the perimeter is less than 78 cm.
5 0
3 years ago
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