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mr Goodwill [35]
3 years ago
8

Is x to the power of two plus x plus 1 a linear expression.

Mathematics
2 answers:
Finger [1]3 years ago
6 0

Answer:

hope it is correct..

Step-by-step explanation:

Yes, it is..

Stolb23 [73]3 years ago
6 0

Answer:

Yes it is

Step-by-step explanation:

I did this question

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Lf g(x) = x3 - 5 and h(x) = 2x - 2, find g(h(3)).
White raven [17]

Answer: g(h(3)) = 59

Step-by-step explanation:

Well if its x^3 I assume it is because you wrote other coefficients before the variable.

2(3) - 2 = 6-2 = 4

So 4 is the x input for h(x)

4^3 -5 = 64-5 = 59

7 0
3 years ago
PLEASE HELP ME!!!!!!!!
Nadusha1986 [10]
CPCTC means the corresponding parts of congruent triangle that are congruent.
So, angle GAE is approximately equal to angle GEA.
3 0
3 years ago
PLEASE HELP I AM STUCK ON THIS
Fofino [41]

Answer:

Step-by-step explanation:

This is a right triangle problem.  The reference angle is x, the side opposite the reference angle is 32, and the hypotenuse is 58.  The trig ratio that relates the side opposite a reference angle to the hypotenuse is the sin.  Filling in accordingly:

sin(x)=\frac{32}{58}

Because you are looking for a missing angle, you will use your 2nd button and then the sin button to see on your display:

sin^{-1}(

Within the parenthesis enter the 32/58 and you'll get your angle measure.  Make sure your calculator is in degree mode, not radian mode!!!

4 0
3 years ago
Solve this equation using the least common denominator ?
Likurg_2 [28]
The answer would be
A. 3/4
6 0
3 years ago
Find the optimal solution for the following problem. (Round your answers to 3 decimal places.)
Sphinxa [80]

Answer:

x=2.125

y=0

C=19.125

Step-by-step explanation:

To solve this problem we can use a graphical method, we start first noticing the restrictions x\geq 0 and  y\geq 0, which restricts the solution to be in the positive quadrant. Then we plot the first restriction 8x+10y\leq 17 shown in purple, then we can plot the second one 11x+12y\leq 25 shown in the second plot in green.

The intersection of all three restrictions is plotted in white on the third plot. The intersection points are also marked.

So restrictions intersect on (0,0), (0,1.7) and (2.215,0). Replacing these coordinates on the objective function we get C=0, C=11.9, and C=19.125 respectively. So The function is maximized at (2.215,0) with C=19.125.

3 0
2 years ago
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