All categories

3 years ago

Fill in the coefficients that will balance the following reaction:

Chemistry

1 answer:

marishachu [46]3 years ago

8 0

Hg(CO₃)₂ + 4AgCl → HgCl₄ + 2Ag₂CO₃

You might be interested in

WILL MARK BRAINLIEST!!<br><br><br> How is a map an example of a model?

bonufazy [111]

A model represents a place thing or idea. A made is a model as it shows a place and represents the place it’s showing such as a globe

7 0

3 years ago

PLSS HELP I GIVE BRAINLIEST

STatiana [176]

What the first person said lol

5 0

2 years ago

Which of the following are polyatomic ions? Check all that apply

stellarik [79]

Answer:

NH4 is the correct ans

Explanation:

Mark as brainliest

6 0

3 years ago

GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g

JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of $H_2$ gas and 1 mole of $Br_2$ liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

$H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ$

Divide the equation by 2.

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

4 0

3 years ago

Does an astronaut have more mass on earth then space? why or why not?

katovenus [111]

Answer:

Explanation:

No, his mass remains the same no matter where he is in the universe.

But then again the moon has less gravitational pull, therefore your weight and mass will be smaller in space and on the moon than on earth

I hope this was helpful! ;)

3 0

3 years ago