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Stolb23 [73]
2 years ago
12

Amino axit X có công thức H2NCxHy(COOH)2. Cho 0,1 mol X vào 0,2 lít dung dịch H2SO4 0,5M, thu được dung dịch Y. Cho Y phản ứng v

ừa đủ với dung dịch gồm NaOH 1M và KOH 3M, thu được dung dịch chứa 36,7 gam muối. Phần trăm khối lượng của nitơ trong X là
Chemistry
1 answer:
Taya2010 [7]2 years ago
7 0

Answer:

nH2SO4 = 0,1 mol

Đặt nNaOH = a; nKOH = 3a (mol)

Quy đổi phản ứng thành: {X, H2SO4} + {NaOH, KOH} → Muối + H2O

Ta có: nH+ = nOH- → 2nX + 2nH2SO4 = nNaOH + nKOH

→ 2.0,1 + 2.0,1 = a + 3a → a = 0,1

→ nH2O = nH+ = nOH- = 0,4 mol

BTKL: mX + mH2SO4 + mNaOH + mKOH = m muối + mH2O

→ mX + 0,1.98 + 0,1.40 + 0,3.56 = 36,7 + 0,4.18 → mX = 13,3 gam

→ MX = 13,3/0,1 = 133

→ %mN = (14/133).100% ≈ 10,526%

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Taking into account the scientific notation,  the result of the subtraction is 6.5×10⁵.

<h3>Scientific notation</h3>

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You want to subtract two numbers in scientific notation. It should be noted that when the numbers to be added do not have the same base 10 exponent, the base 10 power with the highest exponent must be found. In this case, the highest exponent is 5.

Then all the values ​​are expressed as a function of the base 10 exponent with the highest exponent. In this case: 5.00×10⁴=0.500×10⁵

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Finally, the result of the subtraction is 6.5×10⁵.

Learn more about scientific notation:

brainly.com/question/11403716

brainly.com/question/853571

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