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AveGali [126]
3 years ago
8

What are the 6 Steps in the Nitrogen Cycle? Using = NH3, Denitrification, No2 and NO3, Nitrification Bacterial nitrogen fixation

, N2​
Chemistry
1 answer:
algol133 years ago
7 0

Answer:

Nitrogen fixation. Atmospheric nitrogen occurs primarily in an inert form (N2) that few organisms can use; therefore it must be converted to an organic – or fixed – form in a process called nitrogen fixation.

Nitrification.

Assimilation.

Ammonification.

Denitrification.

Explanation:

Does that help? :)

You might be interested in
ose you has aniline as your unknown. What kind of solid derivative would be suitable to synthesize for aniline
gayaneshka [121]

Answer:

Amides are suitable to synthesize aniline

Explanation:

Amide are basically used to synthesize aniline.

The chemical formula of Aniline is C6H5NH2 while that of Amide is RCONH2

Amide are solids that can be easily converted to amines.

4 0
3 years ago
Question 11 (1 point)
iren2701 [21]
Blue to red is acidic, red to blue is basic and no change is neutral.
6 0
3 years ago
The conversion of methyl isonitrile to acetonitrile in the gas phase at 250 °C CH3CN(g) is first order in CH3NC with a rate cons
nadya68 [22]

Answer: The concentration of CH_3NC will be 1.56\times 10^{-2}M after 416 seconds have passed.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant = 3.00\times 10^{-3}s^{-1}

t = age of sample = ?

a = let initial amount of the reactant = 5.45\times 10^{-2}M

a - x = amount left after decay process = 1.56\times 10^{-2}M

t=\frac{2.303}{3.00\times 10^{-3}}\log\frac{5.45\times 10^{-2}}{1.56\times 10^{-2}}

t=416s

The concentration of CH_3NC will be 1.56\times 10^{-2}M after 416 seconds have passed.

5 0
3 years ago
Part B When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 22.8 g of carbon were burned in the pres
aksik [14]

<u>Answer:</u> The amount of carbon dioxide gas produced in the reaction is 83.6 grams

<u>Explanation:</u>

As, some amount of oxygen gas is left after the reaction is completed. So, it is present in excess and is considered as an excess reagent.

Thus, carbon is considered as a limiting reagent because it limits the formation of product.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of carbon = 22.8 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon}=\frac{22.8g}{12g/mol}=1.9mol

The chemical equation for the reaction of carbon and oxygen gas follows:

C+O_2\rightarrow CO_2

By Stoichiometry of the reaction:

1 mole of carbon produces 1 mole of carbon dioxide gas

So, 1.9 moles of carbon will produce = \frac{1}{1}\times 1.9=1.9moles of carbon dioxide gas

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 1.9 moles

Putting values in equation 1, we get:

1.9mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(1.9mol\times 44g/mol)=83.6g

Hence, the amount of carbon dioxide gas produced in the reaction is 83.6 grams

6 0
3 years ago
A discus thrower throws a 1.6kg discus at 25m/s what's the kinetic energy?​
Ilya [14]

Answer:

<h2>500 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2} \\

where

m is the mass

v is the velocity

From the question

m = 1.6 kg

v = 25 m/s

We have

k =  \frac{1}{2}  \times 1.6 \times  {25}^{2}  \\  = 0.8 \times 625 \\  = 500

We have the final answer as

<h3>500 J </h3>

Hope this helps you

6 0
3 years ago
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