I'm assuming that when you wrote "(7x/2-5x+3)+(2x/2+4x-6)," you actually meant "<span>(7x^2-5x+3)+(2x^2+4x-6). Correct me if I'm wrong here.
</span><span>+(7x^2-5x+3)
</span><span>+(2x/2+4x-6)
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=9x^2 - x - 3 (answer) </span>
This shape is separated into two trapezoids. The equation for the area of a trapezoid is .5(base1 + base2) multiplied by height. Therefore, each half of the compound shape would be equal to .5(12 + 8) * 6 or 10 * 6 = 60. So the area of the total would be 60+60 or 120.
37. we know the perimeter of the Box is 30 and two sides are five each so 30-10 is 20 divided by the other two equal size is 10 .
38, The dimension of other in the lids are 10 and a five to find the area if you multiply 10×5 = 50 and you only have to cover 42 sq cm so no you don't have enough eight more sq cm.
Answer:
a3= -343
divade both side by 3 to make a the subject
a3/3= -343/3
a = -114.3